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Luda [366]
2 years ago
8

Please help !!!!!!!!!!!

Mathematics
1 answer:
Dvinal [7]2 years ago
7 0

Answer: 6) x= 17 Same side interior angles sum to 180.

7) x= 3 Alternate exterior angles are equal.

8) x= 35 Corresponding angles are equal.

9) x= 12 Alternate interior angles are equal

Step-by-step explanation:

6) x= Same side interior angles sum to 180.

53+(8x-9)= 180

44+8x= 180

Subtract 44 from both sides

8x= 136

Divide both sides by 8

X = 17

7) x= Alternate exterior angles are equal. 15x+29= 26x-4

Subtract 15x from both sides

29= 11x-4

Add 4 to both sides

33= 11x

Divide both sides by 11

X=3

8) x= Corresponding angles are equal.

4x+7= 6x-63

Subtract 4x from both sides

7 = 2x -63

Add 63 to both sides

70= 2x

Divide both sides by 2

X= 35

9) x= Alternate interior angles are equal

9x+37= 14x-23

Subtract 9 x from both sides

37= 5x -23

Add 23 to both sides

60= 5x

Divide both sides by 5

12=x

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I need help with this tysm​
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Step-by-step explanation:

The function puts a minus sign on 3 times the magnitude of the input.

1. y = -|3×17| = -51

2. y = -|3×10| = -30

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What is the greatest common factor of 12 and 18?
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2 years ago
Find sin(a)&cos(B), tan(a)&cot(B), and sec(a)&csc(B).​
Reil [10]

Answer:

Part A) sin(\alpha)=\frac{4}{7},\ cos(\beta)=\frac{4}{7}

Part B) tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}

Part C) sec(\alpha)=\frac{7}{\sqrt{33}},\ csc(\beta)=\frac{7}{\sqrt{33}}

Step-by-step explanation:

Part A) Find sin(\alpha)\ and\ cos(\beta)

we know that

If two angles are complementary, then the value of sine of one angle is equal to the cosine of the other angle

In this problem

\alpha+\beta=90^o ---> by complementary angles

so

sin(\alpha)=cos(\beta)

Find the value of sin(\alpha) in the right triangle of the figure

sin(\alpha)=\frac{8}{14} ---> opposite side divided by the hypotenuse

simplify

sin(\alpha)=\frac{4}{7}

therefore

sin(\alpha)=\frac{4}{7}

cos(\beta)=\frac{4}{7}

Part B) Find tan(\alpha)\ and\ cot(\beta)

we know that

If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

\alpha+\beta=90^o ---> by complementary angles

so

tan(\alpha)=cot(\beta)

<em>Find the value of the length side adjacent to the angle alpha</em>

Applying the Pythagorean Theorem

Let

x ----> length side adjacent to angle alpha

14^2=x^2+8^2\\x^2=14^2-8^2\\x^2=132

x=\sqrt{132}\ units

simplify

x=2\sqrt{33}\ units

Find the value of tan(\alpha) in the right triangle of the figure

tan(\alpha)=\frac{8}{2\sqrt{33}} ---> opposite side divided by the adjacent side angle alpha

simplify

tan(\alpha)=\frac{4}{\sqrt{33}}

therefore

tan(\alpha)=\frac{4}{\sqrt{33}}

tan(\beta)=\frac{4}{\sqrt{33}}

Part C) Find sec(\alpha)\ and\ csc(\beta)

we know that

If two angles are complementary, then the value of secant of one angle is equal to the cosecant of the other angle

In this problem

\alpha+\beta=90^o ---> by complementary angles

so

sec(\alpha)=csc(\beta)

Find the value of sec(\alpha) in the right triangle of the figure

sec(\alpha)=\frac{1}{cos(\alpha)}

Find the value of cos(\alpha)

cos(\alpha)=\frac{2\sqrt{33}}{14} ---> adjacent side divided by the hypotenuse

simplify

cos(\alpha)=\frac{\sqrt{33}}{7}

therefore

sec(\alpha)=\frac{7}{\sqrt{33}}

csc(\beta)=\frac{7}{\sqrt{33}}

6 0
3 years ago
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