I WILL GIVE BRAINLEST!!!!!!! 6/9x+57=8

Find the area of the missing piece of the polygon and explain your process for finding it:

rusak2 [61]

Answer:

The area of the polygon is 42 $cm^{2}$ .

Step-by-step explanation:

A polygon is a shape that has three or more sides. They are named with respect to the number of their sides. Example, an octagon has 8 sides, hexagon has 6 sides etc.

From the given figure, the area of the shaded polygon can be calculated by;

Area of polygon = Area of square - Sum of areas given

Sum of areas given = 24 + 30 + 48

= 102 $cm^{2}$

The four sides of the figure are equal, thus it is a square. The length of each side is 12 cm, so that:

Area of square = length × width

= 12 × 12

= 144 $cm^{2}$

Area of polygon = 144 - 102

= 42 $cm^{2}$

The area of the polygon is 42 $cm^{2}$ .

6 0

3 years ago

The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is regi

yan [13]

Answer:

We conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

Step-by-step explanation:

We are given that 513 employed persons and 604 unemployed persons are independently and randomly selected, and that 287 of the employed persons and 280 of the unemployed persons have registered to vote.

Let $p_1$ = percentage of employed workers who have registered to vote.

$p_2$ = percentage of unemployed workers who have registered to vote.

So, Null Hypothesis, $H_0$ : $p_1\leq p_2$ {means that the percentage of employed workers who have registered to vote does not exceeds the percentage of unemployed workers who have registered to vote}

Alternate Hypothesis, $H_A$ : $p_1>p_2$ {means that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of employed workers who have registered to vote = $\frac{287}{513}$ = 0.56

$\hat p_2$ = sample proportion of unemployed workers who have registered to vote = $\frac{280}{604}$ = 0.46

$n_1$ = sample of employed persons = 513

$n_2$ = sample of unemployed persons = 604

So, the test statistics = $\frac{(0.56-0.46)-(0)}{\sqrt{\frac{0.56(1-0.56)}{513}+\frac{0.46(1-0.46)}{604} } }$

= 3.349

The value of z test statistics is 3.349.

Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.

Since our test statistic is more than the critical value of z as 3.349 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

5 0

2 years ago

In this rotation WXY is mapped to CBA. if QON = 55, then XOB measures _____.

CaHeK987 [17]

The correct answer would be 1

8 0

3 years ago

Read 2 more answers

Please help on this khan problem i can't word it right so there is attachments for the introductions and options for answers

Gwar [14]

Answer:

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