Answer:
120°
Explanation:
Given forces with magnitude F and F
Applying the parallelogram law of vector
Where resultant is given as :
R = √(A^2 + B^2 + 2ABCos Ф
WHERE A and B are two forces with angle Ф
F =√(F^2 + F^2 + 2F * F Cos Ф
Square both sides
F^2 = F^2 + F^2 + 2F^2 CosФ
F^2 - 2F^2 = 2F^2 CosФ
- F^2 = 2F^2 Cos Ф
Divide both sides by 2F^2
- 1 / 2 = CosФ
Cosine(theta) = - 1/2
Ф = cosi^-1 (-1/2)
Ф = 120°
The asteroid's mass is so small that it has a much smaller acceleration
due to gravity than Earth has. That means that things weigh very very little
on the surface of an asteroid. It also means that the "escape velocity" from
an asteroid is very low, and orbital velocities are very low at any distance off
of its surface.
As an extreme example: You know how when you walk, you naturally rise up
on the toes of one foot while you reach out with the other one to take a step ?
All of those motions are what you learn in Earth's gravity. On an asteroid, that
natural action of rising up on your toes might launch you into a long, high arc,
like a golf ball. Or it might even exceed escape velocity and you'd sail up off
of the asteroid and never come back down to it.
Answer:
a. El peso = 686 Newton
b. El peso = 113.4 Newton
Explanation:
Dados los siguientes datos;
Masa = 70 kg
Aceleración debida a la gravedad en la luna = 1,62 m/s² una.
a. Para encontrar la fuerza-peso en la Tierra;
Sabemos que la aceleración debida a la gravedad es igual a 9,8 m/s² en el planeta Tierra.
El peso se puede definir como la fuerza que actúa sobre un cuerpo o un objeto como resultado de la gravedad.
Matemáticamente, el peso de un objeto viene dado por la fórmula;
Dónde;
m es la masa del objeto.
g es la aceleración debida a la gravedad.
Substituting into the formula, we have;
El peso = 70 * 9.8
El peso = 686 Newton
b. To find weight on moon;
Weight = mass * acceleration due to gravity on moon
Weight = 70 * 1.62
Weight = 113.4 Newton
Answer:
The second vector
points due West with a magnitude of 600N
Explanation:
The original vector
points with a magnitude of 200N due east, the Resultant vector
points due west (that's how east/west direction can be interpreted, from east to west) with a magnitude of 400N. If we choose East as the positive direction and West as the negative one, we can write the following vectorial equation:

With the negative sign signifying that the vector points west.