1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sveticcg [70]
3 years ago
6

WILL GIVE BRAINLIEST!!

Physics
1 answer:
Rudiy273 years ago
8 0

Answer:

B. NEWTONS SECOND LAW

Explanation:

I believe

You might be interested in
Instrumento que se utiliza para medir fuerzas
Klio2033 [76]

Answer:

Un medidor de fuerza

A force gauge for all you English speakers

Explanation:

Un medidor de fuerza es un instrumento de medición que se utiliza para medir fuerzas.

A force gauge is a measuring instrument used to measure forces.

8 0
3 years ago
In which one of the following situations is zero net work done? A) A ball rolls down an inclined plane. B) A physics student str
lidiya [134]

Answer:

Option D

Explanation:

The work done can be given by the mechanical energy used to do work, i.e., Kinetic energy and potential energy provided to do the work.

In all the cases, except option D, the energy provided to do the useful work is not zero and hence work done is not zero.  

In option D, the box is being pulled with constant velocity, making the acceleration zero and thus Kinetic energy of the system is zero. Hence work done in this case is zero.

6 0
3 years ago
Read 2 more answers
A charged object traveling 7 m in a uniform electric field of 5 N/C experiences a 4 J increase in Kinetic Energy.
Travka [436]

To solve this problem it is necessary to apply the principles of conservation of Energy in order to obtain the final work done.

The electric field in terms of the Force can be expressed as

E = \frac{F}{q} \rightarrow F=Eq

Where,

F = Force

E= Electric Field

q = Charge

Puesto que el trabajo realizado es equivalente al cambio en la energía cinetica entonces tenemos que

KE = W

KE = F*d

In the First Case,

4 = (qE)d\\q = \frac{4}{Ed}\\q = \frac{4}{5*7}\\q = 0.1142C

In Second Case,

KE = q E'd

KE = (0.1142)(40)(7)

KE = 31.976J

The total energy change would be subject to,

\Delta KE = 31.976-4

\Delta KE = 27.976J

Therefore the Kinetic Energy change of the charged object is 27.976J

3 0
2 years ago
When observing an object, you determine it is moving at a constant velocity and in a straight line. Which of these BEST describe
Marina86 [1]
The answer would be C. Hope this helps XD
8 0
3 years ago
Read 2 more answers
Juans mother drives 7.25 miles southwest to her favorite shopping mall. What is the average velocity of her automobile if she ar
Irina-Kira [14]
21.75 Miles Per Hour

I got this by multiplying 7.25(3) because I know 20 minutes is 1/3 of 1 he
5 0
3 years ago
Other questions:
  • When is thermal equilibrium achieved between two objects
    11·1 answer
  • A circular loop of wire has radius of 9.50 cmcm. A sinusoidal electromagnetic plane wave traveling in air passes through the loo
    5·1 answer
  • What is the biggest disadvantage of solar electricity, or at least, why is it not used much more than it currently is?
    15·1 answer
  • If you ride your bike at an average speed of 4 km/h and need to travel a total distance of 28 km,how long will it take you to re
    15·2 answers
  • A loop circuit has a resistance of R1 and a current of 2 A. The current is reduced to 1.5 A when an additional 1.6 Ω resistor is
    13·2 answers
  • A flat, circular, copper loop of radius r is at rest in a uniform magnetic field of magnitude B that extends far beyond the edge
    9·1 answer
  • Amy uses 20 N of force to push a lawnmower 10 meters. How much work does she do?
    9·1 answer
  • What is the speed of light in a vacuum?
    9·2 answers
  • Greyhounds are among the fastest dogs on earth. On average, what is the fastest speed they can run?.
    6·1 answer
  • Sofia needs to go to the grocery store. She leaves her house, walks 1 mi north
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!