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sveticcg [70]
3 years ago
6

WILL GIVE BRAINLIEST!!

Physics
1 answer:
Rudiy273 years ago
8 0

Answer:

B. NEWTONS SECOND LAW

Explanation:

I believe

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Which of the following can break solid rock
sergeinik [125]

I would think the answer would be c

7 0
3 years ago
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It is measured that 3/4 of a body's volume is submerged in oil of density 800kg/m³
Evgesh-ka [11]

Complete question:

It is measured that 3/4 of a body's volume is submerged in oil of density 800kg/m³. What is the specific gravity of oil?

Answer:

The specific gravity of the oil is 0.8.

Explanation:

Given;

density of the oil, \rho_o = 800 kg/m³

density of water, \rho_w = 1000 kg/m³

The specific gravity of any substance is the ratio of the substance density to the density of water.

Specific gravity of the oil = density of the oil / density of water

Specific gravity of the oil = 800/1000

Specific gravity of the oil = 0.8

Therefore, the specific gravity of the oil is 0.8.

8 0
3 years ago
At what height h above the ground does the projectile have a speed of 0.5v?
dedylja [7]

Answer:height above ground at which projectile have velocity

0.5v is (0.0375v^2)

Explanation:

Using Vf = Vi - gt

Where Vf is final velocity

Vi is initial velocity

g is the acceleration due to gravity

t is the time taken

So, 0.5v = v - gt

t = 0.05v

Therefore height h = vt - 0.5gt^2

Subtitute t

h = 0.05v^2 - 0.0125v^2

h = 0.0375v^2

3 0
3 years ago
redacteaza un text in care sa iti exprimi parerea in legaturacurtamentul golegilor din textul oracolul
Ivahew [28]

Answer:

Seriously I have no idea. I need help with my homework.

Explanation:

I really need help with my homework. Sorry

4 0
3 years ago
radio signals emitted from and received by an airplane have her fruit frequency of 3.00 * 10 to the 12th Hertz and travel at the
Elanso [62]

here we know that the speed of the signal is same as the speed of light

so here we will have

v = 3 \times 10^8 m/s

the altitude of the airplane is given as

h = 1 \times 10^4 m

now we know that time taken by the signal to reach the control tower is given as

t = \frac{d}{v}

now it is given as

t = \frac{1 \times 10^4 }{3 \times 10^8}

t = 3.33 \times 10^{-5} s

so above is the time taken by the signal to reach the control tower

3 0
4 years ago
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