To solve this problem we will apply the concepts related to Newton's second law for which the product of mass and acceleration is defined as the force applied to an object. Mathematically this is,
Here,
Net external Force
m = Mass of the body
a = Acceleration
The net force on the body would be given by the difference between the ascending force and the weight, therefore,
Here,
F = Upward Force
W = Weight
The Weight is,
Then the is
Finally replacing at the first equation we have,
Therefore the acceleration of the stone is
We are given
m = mass of the object
r = distance from the center of the planet
r <span>≥ rplanet
We are asked for the
ve = escape velocity
The escape velocity
ve = </span>√ (2Gm/r)
<span>
</span>
Answer:
a) 6076 m
b) 43.33 m/s
c) 68 m/s
Explanation:
(a) If the airplane rounds half the circle in 156s, its displacement is the circle diameter in 156s, or twice the circle's radius
s = 2r = 2* 3.38km = 6.76 km or 6760 m
(b) The average velocity would be displacement over unit of time
v = s/t = 6760 / 156 = 43.33 m/s
(c) The length of the chord it's swept in 156s is half of the circle perimeter
c = πr = π3.38 = 10.62 km or 10620 m
The airplane average speed is its chord length over a unit of time
c / t = c / 156 = 68 m/s
Answer:
B will take 1.034 times the time of A from Boston to Hartford.
Explanation:
Let the distance from Boston to Hartford be S.
Person A drives at a constant speed of 55 mph for the entire trip,
Time taken by person A
Person B drives at 65 mph for half the distance and then drives 45 mph for the second half of the distance.
Time taken by person B
Ratio of time of arrival of B to A
B will take 1.034 times the time of A from Boston to Hartford.
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