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fgiga [73]
3 years ago
7

A college student takes out a $7000 loan from a bank. The bank charges 5,6% interest per year. How much will

Mathematics
2 answers:
Yuki888 [10]3 years ago
6 0
This is what I came up with

hichkok12 [17]3 years ago
4 0

Answer:

$392

Step-by-step explanation:

5.6% of $7000 is 392

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3 years ago
Explain how to make a precise graph of y = -2x + 3 without making a T-Table.
kifflom [539]

Answer:

x 2 + 5 x + 6

Step-by-step explanation:

y = m x + c

y- intercept

x = 0

y = (-2) (0) + 3

=3

(x =0,  y = 3)

<h3>slope -2 </h3><h3>y = -1 x + 3</h3>
8 0
3 years ago
How much more would $1,000 earn in 5 years in an account compounded continuously than an account compounded quarterly if the int
s2008m [1.1K]

Answer: There is a difference of $ 1.0228.

Explanation: Given, initial amount or principal = $ 1000,

Time= 5 years and given compound rate of interest = $3.7%

Now, Since the amount in compound continuously,

A= Pe^{rt} , where, r is the rate of compound interest, P is the principal amount and t is the time.

Here, P=$ 1000, t=5 years and r= $3.7%,

Thus, amount in compound continuously ,  A=1000e^{3.7\times5/100}

⇒A=1000e^{18.5}=1000\times 1.20321844013=1203.21844013

Therefore, interest in this compound continuously rate =1203.21844013-1000=203.21844013

now, Since the amount in compound quarterly,

A=P(1+\frac{r/4}{100} )^{4t}, where, r is the rate of compound interest, P is the principal amount and t is the time.

Thus, amount in compound quarterly, A=1000(1+\frac{3.7/4}{100} )^{4\times5}

⇒A=1000(1+\frac{3.7}{400} )^{20}

⇒A=1000(1+\frac{3.7}{400} )^{20}

⇒A= 1202.19567617

Therefore, interest in this compound quarterly rate=1202.19567617-1000=202.19567617

So, the difference in these interests=203.21844013-202.19567617=1.02276396 ≈1.0228                                                  

4 0
3 years ago
Read 2 more answers
Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance. For what fraction of
Kruka [31]

Answer:

Lola was in lead for \frac{6}{25} of a mile.

Step-by-step explanation:

We have been given that Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance.

To find the fraction of a mile for which Lola was in the lead, we need to find 4/5 of 3/10 as:

\text{Fraction for which Lola was in lead}=\frac{3}{10}\times\frac{4}{5}

\text{Fraction for which Lola was in lead}=\frac{3}{5}\times\frac{2}{5}

\text{Fraction for which Lola was in lead}=\frac{3\times2}{5\times5}

\text{Fraction for which Lola was in lead}=\frac{6}{25}

Therefore, Lola was in lead for \frac{6}{25} of a mile.

7 0
3 years ago
Write an inequality for the graph
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Answer is d
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8 0
3 years ago
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