Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
Ok so if you did 156-6 (considering it was 6 more you want to subtract it) and then because the girls was doubled the boys (you are now at 150) you must divide that by 3 which will give you 50. But you need to double it (for girls) which is 100 and then you have 50 left over which is for the boys. Boys=50 girls=106
Dear Student,
Answer to your query is provided below:
The length of segment AB = 8
Explanation to answer is provided by attaching image.
Which question do you need answered or both?
