Question

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Answer 1

Answer:

a)    

       R R

R RR RR

r Rr Rr

Genotypic ratio:  RR : Rr = 2 : 2 = 1: 1

Phenotypic ratio: homozygous red bull (RR)  :  heterozygous red cow (Rr) = 2:2 = 1: 1

b)

     R r

R RR Rr

r Rr rr

Genotypic ratio:  RR : Rr:rr = 1:2:1

Phenotypic ratio: homozygous red bull (RR)  :  heterozygous red cow (Rr) : homozygous white bull (rr) = 1: 2: 1

c)

Xr Yr

Xr Xr Xr Xr Yr

Xr Xr Xr Xr Yr

Genotypic ratio:  Xr Xr: Xr Yr  = 2: 2 = 1: 1

Phenotypic ratio: homozygous white cow (Xr Yr)  :  heterozygous white bull (Xr Yr) = 2: 2 = 1: 1

Explanation:

a)

First cross is between a a homozygous red bull (RR) and a heterozygous red cow (Rr)

This shows that "Red" color is a dominant trait

So the cross between Rr and RR is

      R R

R RR RR

r Rr Rr

Genotypic ratio:  RR : Rr = 2 : 2 = 1: 1

Phenotypic ratio: homozygous red bull (RR)  :  heterozygous red cow (Rr) = 2:2 = 1: 1

b)

Cross between a heterozygous red bull (Rr) and a heterozygous red cow (Rr)

R r

R RR Rr

r Rr rr

Genotypic ratio:  RR : Rr:rr = 1:2:1

Phenotypic ratio: homozygous red bull (RR)  :  heterozygous red cow (Rr) : homozygous white bull (rr) = 1: 2: 1

c)

Cross between a homozygous white bull (rr) and a homozygous white cow (rr)

Xr Yr

Xr Xr Xr Xr Yr

Xr Xr Xr Xr Yr

Genotypic ratio:  Xr Xr: Xr Yr  = 2: 2 = 1: 1

Phenotypic ratio: homozygous white cow (Xr Yr)  :  heterozygous white bull (Xr Yr) = 2: 2 = 1: 1

Answer 2

A)





Therefore:Crossing results in 50% (dominant homozygote) and 50% (dominant heterozygote).
b)





Therefore:Crossing results in 25% (dominant homozygote), 50% (dominant heterozygote) and 25% (homozygous recessive).
c)





Therefore:Crossing results in 100% (homozygous recessive).