Two lines are perpendicular if their slope m and m' satisfy the equation
The slope of the given line is 4, because the line is written in the slope-intercept y=mx+q, where m is the slope.
So, the perpendicular slope is
So, we want a line with slope -1/4 and passing through (-1,3). We can use the formula
for the line passing trough (a,b) with slope m:
Answer:
wait ill work this out for you
Step-by-step explanation:
The domain and range of the given function are equal to (0, 3.85) and (0, 18.75) respectively.
<h3>How to calculate the domain of the function?</h3>
In this exercise, you're given the following function h(t) = -4.87t² + 18.75t. Next, we would equate the function to zero (0) to determine its domain as follows:
0= -4.87t² + 18.75t.
4.87t(-t + 3.85) = 0
t = 0 or t = 3.85.
Therefore, the domain is 0 ≤ t ≤ 3.85 or (0, 3.85).
<h3>How to calculate the range of the function?</h3>
h(t) = -4.87t² + 18.75t
h(t) = -4.87(t² - 3.85t + 3.85 - 3.85)
h(t) = -4.87(t - 1.925)² + 18.05
Therefore, the range is 0 ≤ h ≤ 18.05 or (0, 18.75).
Read more on domain here: brainly.com/question/17003159
#SPJ1
