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2 years ago

Please help me to solve this problem

Mathematics

2 answers:

Vikentia [17]2 years ago

7 0

Answer:

x=3

Step-by-step explanation:

Andrews [41]2 years ago

3 0

$\LARGE{ \underline{ \tt{Required \: answer:}}}$

To Solve:

$\large\rm{ { \dfrac{3}{5} }^{x} . { \dfrac{5}{3} }^{2x} = \dfrac{125}{27} }$

Solution:

$\large\rm{ \leadsto { \dfrac{5}{3} }^{ - x}. { \dfrac{5}{3} }^{2x} = \dfrac{5 {}^{3} }{3 {}^{3} } }$

$\large \rm{ \leadsto \dfrac{5 {}^{2x - x} }{ {3}^{2x - x} } } = \dfrac{5 {}^{3} }{ {3}^{3} }$

$\large \rm{ \leadsto \dfrac{5 {}^{x} }{ {3}^{x} } = \dfrac{5 {}^{3} }{ {3}^{3} } }$

$\large\rm{ \leadsto { \bigg( \dfrac{5}{3} \bigg) }^{x} = \bigg( \dfrac{5}{3} \bigg) ^{3} }$

Then,

$\large{ \boxed{ \rm{x = 3}}}$

The required value of x is <u>3</u><u>.</u>

⛱️ $\large{ \blue{ \bf{FadedElla}}}$

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1.Assume that 20 squirrels are put in an enclosed wildlife ranch and the squirrel population grows for the next 5 years, as show

stiv31 [10]

Answer:

For the first group we have the pairs:

year population

0 20

1 80

2 320

3 1,280

4 5,120

5 20,480

Here we can see that the population quadruples each year

(4*20 = 80, 80*4 = 320, 320*4 = 1,280, etc...)

then the population equation is:

P(0) = 20

P(1) = 20*4

P(2) = (20*4)*4 = 20*4^2

We already can see the pattern, then we can write this relationship as:

P(t) = A*(4)^(t)

Where:

t represents time in years, and A is the initial population, that we know it is 20, then:

P(t) = 20*(4)^t

This is the function that represents the table.

B) Now we have a group of 20 squirrels and the population triples each year, with the same reasoning than before we can write the equation that models this situation as:

Q(t) = 20*(3)^t

C) Now, if the initial population of the second group is 40, the equation becomes:

Q(t) = 40*(3)^t

The population by year 3 is given by replacing t by 3, then:

Q(3) = 40*(3)^3 = 1080

And the population of the other group in year 3 is seen in the table, it is 1,280, then the population of the first group is bigger by year 3, and it is greater by:

1,280 - 1,080 = 200

So the first group is larger by 200 squirrels.

3 0

2 years ago

The axis of symmetry of the graph of h is x = - 3. which ordered pair represents the additional point on the graph of h?

Tresset [83]

Answer: (1,-5)

Step-by-step explanation:it’s the answer

4 0

2 years ago

A rectangle has a height of 777 and a width of 2x^2-32x

Murljashka [212]

<h2>Explanation:</h2><h2></h2>

Hello! Remember you have to write clear questions in order to get good and exact answers. Here I'll assume the data given in a comment above. So:

$H:height \\ \\ W:Width \\ \\ \\ H=7 \\ \\ W= 2x^2-32x+2$

We know that the area (A) of any rectangle is given by:

$A=H\times W \\ \\ A=7(2x^2-32x+2) \\ \\ \\ Expanding: \\ \\ A=(7)(2x^2)-(7)(32x)+(7)(2) \\ \\ \boxed{A=14x^2-224x+14}$

8 0

3 years ago

Determine the equations you would use to represent the situation.

ASHA 777 [7]

Answer:

You sold 20 student tickets.

Step-by-step explanation:

Given that:

Total tickets sold = 27

Total amount collected = $170

Cost of student ticket = $5

Cost of adult ticket = $10

Let,

x be the number of students tickets sold

y be the number of adult tickets sold

x+y = 27 Eqn 1

5x+10y=170 Eqn 2

Multiplying Eqn 1 by 10

10(x+y=27)

10x+10y=270 Eqn 3

Subtracting Eqn 2 from Eqn 3

(10x+10y)-(5x+10y)=270-170

10x+10y-5x-10y=100

5x=100

Dividing both sides by 5

$\frac{5x}{5}=\frac{100}{5}\\x=20$

Hence,

You sold 20 student tickets.

3 0

2 years ago

Simplify this expression <br> Thank you :)

Anna11 [10]

Im not entirely sure but i got 3x^2y

6 0

2 years ago

Please help me to solve this problem ​

Please help me to solve this problem