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dedylja [7]
2 years ago
11

Please help me to solve this problem ​

Mathematics
2 answers:
Vikentia [17]2 years ago
7 0

Answer:

x=3

Step-by-step explanation:

Andrews [41]2 years ago
3 0

\LARGE{ \underline{ \tt{Required \: answer:}}}

To Solve:

  • \large\rm{  { \dfrac{3}{5} }^{x} . { \dfrac{5}{3} }^{2x}  =  \dfrac{125}{27} }

Solution:

\large\rm{ \leadsto   { \dfrac{5}{3} }^{ - x}. { \dfrac{5}{3} }^{2x}  =  \dfrac{5 {}^{3} }{3 {}^{3} }  }

\large \rm{ \leadsto \dfrac{5 {}^{2x - x} }{ {3}^{2x - x} }  } =  \dfrac{5 {}^{3} }{ {3}^{3} }

\large \rm{ \leadsto  \dfrac{5 {}^{x} }{ {3}^{x} }  =  \dfrac{5 {}^{3} }{ {3}^{3} } }

\large\rm{ \leadsto  { \bigg( \dfrac{5}{3} \bigg) }^{x}  =  \bigg( \dfrac{5}{3} \bigg) ^{3}   }

Then,

  • \large{ \boxed{ \rm{x = 3}}}

The required value of x is <u>3</u><u>.</u>

⛱️ \large{ \blue{ \bf{FadedElla}}}

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pishuonlain [190]
Hello,

10 is not a digit!
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3 years ago
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sertanlavr [38]

Answer:

the area of the shape is 7.14

Step-by-step explanation:

First, find the area of the square:

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A certain semiconductor device requires a tunneling probability of T = 10-5 for an electron tunneling through a rectangular barr
Goryan [66]

Answer:

Generally the barrier width is a = 1.9322 *10^{-9} \ m

Step-by-step explanation:

From the question we are told that

     The tunneling probability required is  T  = 1 * 10^{-5}

      The barrier height is  V_o  = 0.4 eV

       The electron energy is  E = 0.08eV

Generally the wave number is mathematically represented as

      k  =  \sqrt{ \frac{2 * m [V_o - E]}{\= h^2} }

Here m is the mass of the electron with the value  m  =  9.11 *10^{-31} \  kg

         h  is is know as h-bar and the value is  \= h = 1.054*10^{-34} \  J \cdot s

So

          k  =  \sqrt{ \frac{2 * 9.11 *10^{-31 } [0.4 - 0.04] * 1.6*10^{-19}}{[1.054*10^{-34}^2]} }

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Generally the tunneling probability is mathematically represented as

          T  = 16 * \frac{E}{V_o }  * [1 - \frac{E}{V_o} ] * e^{-2 * k * a}

So

        1.0 *10^{-5} = 16 * \frac{0.04}{0.4 }  * [1 - \frac{0.04}{0.4} ] * e^{-2 * 3.0736 *10^{9} * a}

=>    6.944*10^{-6}= e^{-2 * 3.0736 *10^{9} * a}

Taking natural log of both sides

          ln[6.944*10^{-6}] = -2 * 3.0736 *10^{9} * a}

=>        -11.8776  = -2 * 3.0736 *10^{9} * a}

=>        a = 1.9322 *10^{-9} \ m

       

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Answer:

Step-by-step explanation:

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