You will have 1 and 1/18 properly, or 19/18 in an improper fraction.
Answer:
69 need to be added
Step-by-step explanation:
1300 +69 = 1369
37 ² = 1,369
square root of 1,369 is 37
The changes in Z would be = 6.1× 10^-4.
<h3>Calculation of the unknown value</h3>
Z = Sin (x³ +y³)
Where X = 0.3
y = 0.2
Z= Sin ( 0.3³ + 0.2³)
Z= Sin ( 0.027 + 0.008)
Z= Sin ( 0.035)
Z= 6.1× 10^-4
Therefore, the changes in Z would be = 6.1× 10^-4.
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Weight of an grapefruit=weight of an orange+8% weight of an orange
weight of an apple=weight of an orange -10% weight of an orange
a.<span>By what percentage is the grapefruit heavier than the apple?
We should find the connection between grapefruit and an apple. We know the connection between the weight of a grapefruit and an orange, we know the connection between an orange and an apple, so this means we know the connection between a grapefruit and an apple.
</span>
weight of an grapefruit=weight of an <span>orange+8% weight of an orange
</span>weight of an orange=weight of an apple<span> +10% weight of an apple
</span>
-> weight of an grapefruit=weight of an apple+10% weight of an apple + 8%(weight of an apple+10% weight of an apple)= weight of an apple + 18% weight of an apple + 2% weight of an apple= <span>weight of an apple + 20% weight of an apple
</span><span>b.By what percentage is the apple lighter than the grapefruit?
</span>weight of an grapefruit=weight of an apple + 20% weight of an apple<span>
</span>
-> The apple ts 20% lighter than the grapefruit.
Answer:
The histogram of the sample incomes will follow the normal curve.
Step-by-step explanation:
According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.
In this case the researches wants to determine the monthly gross incomes of drivers for a ride sharing company.
He selects a sample of <em>n</em> = 200 drivers and ask them their monthly salary.
As the sample selected is quite large, i.e. <em>n</em> = 200 > 30, the central limit theorem can be applied to approximate the sampling distribution of sample mean by the Normal distribution.
Thus, the histogram of the sample incomes will follow the normal curve.