Answer:
55.2° ...............................
At the point when Hannah takes her first sweet from the sack, there is a 6/n chance it is orange.
This is because that there are 6 orange desserts and n desserts altogether.
When Hannah takes out her second sweet, there is a 5/(n-1) chance that it is orange.
This is because there are just 5 orange desserts let alone for an aggregate of n-1 desserts.
The possibility of getting two orange desserts in succession is the main likelihood increased by the second one: 6/n x 5/n–1
The question lets us know that the shot of Hannah getting two orange desserts is 1/3.
So: 6/n x 5/n–1 = 1/3
Now, rearrange this problem.
(6x5)/n(n-1) = 1/3
This gets to be:
30/(n² – n) = 1/3
Times by 3 on both sides:
90/(n² – n) = 1
What's more, doing likewise with (n² – n):
So (n² – n) = 90
Our answer is: n² – n – 90 = 0
Answer:4
Step-by-step explanation:
Because it’s the right answer
To find the sale price<span> we can set up a proportion. 25/100 = </span>x<span>/48. We keep the 100 and 48 both on the bottom of the fraction since they </span>represent<span> the "whole". </span>x represents<span> the </span>discount<span> off the </span>full price<span> of the dress. To solve this proportion, we cross multiply, yielding 48 * 25 = 100x. Alternatively, </span>if<span> you notice that 25/100 ...</span>
