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velikii [3]
3 years ago
13

A polyhedron has 6 vertices and 9 edges. How many faces does it have?

Mathematics
2 answers:
Sidana [21]3 years ago
7 0
5 faces
The polyhedron is a Triangular Prism.
arlik [135]3 years ago
3 0

Answer:

B

Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
Please help me !!
Brut [27]
The answers to your questions are 1.D, and 2.C
8 0
2 years ago
Read 2 more answers
[HELP ASAP 50 POINTS] 17, 18, 19, 20
Charra [1.4K]

17) f(x) = 16/(13-x).

In order to find domain, we need to set denominator expression equal to 0 and solve for x.

And that would be excluded value of domain.

13-x =0

Adding x on both sides, we get

13-x +x = x.

13=x.

Therefore, domain is All real numbers except 13.



18).f(x) = (x-4)(x+9)/(x^2-1).

In order to find the vertical asymptote, set denominator equal to 0 and solve for x.

x^2 -1 = 0

x^2 -1^2 = 0.

Factoring out

(x-1)(x+1) =0.

x-1=0 and x+1 =0.

x=1 and x=-1.

Therefore, Vertical asymptote would be

x=1 and x=-1

19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)

We have degrees of numberator and denominator are same.

Therefore, Horizontal asymptote is the fraction of leading coefficents.

That is 7/2.


20) f(x)=(x^2+3x-2)/(x-2).

The degree of numerator is 2 and degree of denominator is 1.

2>1.

Degree of numerator >  degree of denominator .

Therefore, there would no any Horizontal asymptote.

6 0
3 years ago
Will give brainliest!!!
Igoryamba

y = 80x - 60

Answer is B. y = 80x - 60

Double check:

When x = 1, y = 80(1) - 20 = 80 -60 = 20

When x = 2, y = 80(2) - 20 = 160 -60 = 100

When x = 3, y = 80(3) - 20 = 240 -60 = 180

When x = 4, y = 80(4) - 20 = 320 -60 = 260

When x = 5, y = 80(5) - 20 = 400 -60 = 340

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3 years ago
You see, I can be myself now finally
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The song is 'Hey, Soul Sister' by Train. The next 29 words are:

I want the world to see you be, with me

Hey, soul sister

Ain't that Mr. Mister on the radio, stereo?

The way you move ain't fair, you know

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3 years ago
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