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Zanzabum
2 years ago
14

Solve on the interval [0,2pi):

Mathematics
1 answer:
mel-nik [20]2 years ago
4 0

Answer:

B

Step-by-step explanation:

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3 years ago
Please help<br> thank you again
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<em><u>Answer:</u></em>

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3 years ago
A population of rabbits in a lab, p(x), can be modeled by the function p(x) = 20(1.014)x , where x represents the number of days
Nitella [24]

Answer:

20 = initial population of the rabbits

1.014 = growth rate of the rabbits

the average rate of change from day 50 to day 100 is 0.8

Step-by-step explanation:

A population of rabbits in a lab, p(x), can be modeled by the function

p(x) = 20(1.014)^x

This model is exponential. Where 20 = initial population of the rabbits

1.014 = growth rate of the rabbits with 1.4% increase rate of the rabbits

To find the average rate of change from day 50 to day 100,

find the population p(50) and p(100). Subtract them and divide by 100 - 50 = 50. 

p(50) = 20(1.014)50 = 40.08... 

p(100) = 20(1.014)100 = 80.32... 

(80.32 - 40.08) / (100 - 50) = 40.24/50 = 0.8048. which is approximately 0.8 to the nearest tenth. 

The rate of change is 0.8. 

7 0
3 years ago
4 Jillian's school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket salesfor
Kitty [74]
$10.50a + $3.75b = $2,071.50 It is given that b = 82 Therefore - $10.50a + ($3.75)(82) = $2,071.50 or $10.50a + $307.50 = $2,071.50 $10.50a = $2,071.50 - $307.50 = $1,764.00 Therefore - a (number of adult tickets sold) = $1,764.00/$10.50 = 168 tickets
4 0
3 years ago
Read 2 more answers
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