Interesting question
Usually when you look at something like that construction, you think that AB has been bisected by PQ and that the two segments are perpendicular. They are perpendicular but nowhere is that stated. So the answer is C because all the other answers are wrong.
PQ is congruent AB is not correct. As long as the arcs are equal and meet above and below AB there is no proof of congruency. In your mind widen the compass legs so that they are wider than AB and redraw the arcs. You get a larger PQ, but it has all the original properties of PQ except size.
PQ is not congruent to AQ. How would you prove conguency? You'd have to put both lines into triangles that can be proved congruent. It can't be done.
The two lines are not parallel. They are perpendicular. That can be proven. They meet at right angles to each other (also provable).
Answer:
the answer is 12
Step-by-step explanation
first you got to divide the 12 and the 3 which is 4
then you got to add 8 and 22 which would get you 30 and then bring the times 2 down and the multiply it to the 4 which is 8 and then you subtract the 30 and the 8 and then you'll get 12
Let the angle be y;
Then the supplement is 5y
y+5y=180
6y=180
y=30
The angle is 30 degrees
I'm pretty sure it's 1/10 because it is one out of ten instead of one out of 12 ya feel
Answer:
y= -5x +7
Step-by-step explanation:
We can see points on the graph:
The function in general form is:
Let's find the slope and y-intercept as per identified points on the graph:
b= y- mx
- b= - 3 -(-5)*2= -3 +10= 7
Based on the found values of m and b, the given line is:
