Answer:
8 dollars per hour
Step-by-step explanation:
You make 92 a week
20 of that is from your allowance
92-20 = 72
72 is from your part time job
You work for 3 hours on Friday and 6 hours on Saturday, for a total of 3+6 = 9 hours
Take the amount of money earned and divide by the number of hours to determine the money earned per hour
72/9 = 8 dollars per hour
To solve this, we need to understand Slope Intercept Form (SIF), as well as how to graph a line.
SIF is the standard equation of lines on graphs. It is "y=mx+b" where m is the slope and b is the y-intercept. The y-intercept is the value of y when x is 0.
To find the y-intercept (which we will need to form the equation), we should simply graph the line. This will let us visualize the y-intercept, and overall make it easier to understand.
To graph a line, we should start with the point we have (that being (3, 3)) and follow the slope with rise/run. This means in this case, we will go right 2 for every 1 up, or 2 left for every 1 down.
Below I have attached a graph to help you see how to graph this, which we will get our equation from. The highlighted area is our y-intercept. The red circle shows our original point (3,3), and the blue dots show our slope.
Using the graph, we can see the equation for this line is
y=1/2x+1.5.
In math it means to make a problem easier to work with
Given that the chip has a dimension of 8 mm by 8 mm which can be written as 0.8 cm by 0.8 cm, is drawn to scale and the dimensions of the plot is 4 cm by 4 cm, the scale of the drawing will be:
0.8 cm is represented by 4 cm
thus;
4 cm rep 0.8 cm
1 cm rep 0.2 cm
The answer is:
1 cm rep 0.2 cm
Answer:
Step-by-step explanation:
Given that:
Population Mean = 7.1
sample size = 24
Sample mean = 7.3
Standard deviation = 1.0
Level of significance = 0.025
The null hypothesis:

The alternative hypothesis:

This test is right-tailed.

Rejection region: at ∝ = 0.025 and df of 23, the critical value of the right-tailed test 
The test statistics can be computed as:



t = 0.980
Decision rule:
Since the calculated value of t is lesser than, i.e t = 0.980 <
, then we do not reject the null hypothesis.
Conclusion:
We conclude that there is insufficient evidence to claim that the population mean is greater than 7.1 at 0.025 level of significance.