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grin007 [14]
3 years ago
10

Hey can you please help me posted picture of question

Mathematics
1 answer:
enyata [817]3 years ago
4 0
If the total area of a dartboard 30 000 mm² and the area of the target is 700 mm²
 The probability of obtaining a target can be written as:
 P = 700 mm² / 30 000 mm²
 P = 0.0233
 P = 2.3%
 Therefore the correct answer is option B.
 This, assuming the shooter has no experience and rolls the dart randomly within the dartboard area.
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Answer:

15 scores are less than 90

Step-by-step explanation:

Total 11 scores are less than 90 not 15

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Whats the value of 1/6^0? 1/6 0 1
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Answer:

1    (anything with the exponent of 0 always equals 1)

Step-by-step explanation:

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In a recent year, a sample of grade 8 Washington State public school students taking a mathematics assessment test had a mean sc
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Answer:

The  number is  N  =1147 students

Step-by-step explanation:

From the question we are told that

    The population mean is  \mu  =  281

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    The sample size is  n = 2000

percentage of the would you expect to have a score between 250 and 305 is mathematically represented as

      P(250 <  X <  305 ) =  P(\frac{ 250 - 281}{34.4 }  <  \frac{X - \mu }{\sigma }  < \frac{ 305 - 281}{34.4 }   )

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             \frac{X - \mu }{\sigma }  =  Z  (Standardized \ value \  of  \  X )

So  

         P(250 <  X <  305 ) =  P(-0.9012<  Z

       P(250 <  X <  305 ) = P(z_2 < 0.698 ) -  P(z_1 <  -0.9012)

From the z table  the value of  P( z_2 < 0.698) =  0.75741

                                         and  P(z_1 < -0.9012) =  0.18374

     P(250 <  X <  305 ) = 0.75741 - 0.18374

      P(250 <  X <  305 ) =  0.57

The  percentage is  P(250 <  X <  305 ) =  57\%

The  number of students that will get this score is

           N  = 2000 * 0.57

           N  =1147

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How to graph y=-x+4 and the table for it
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Answer:

Here are pictures of the graph and corresponding table. Hope this helps!

Step-by-step explanation:

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i am planning to attend a company-paid conference. My charges will include $412.00 for airfare, $ 378.00 for conference registra
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The estimated expense would be about $1000.00 in which taxzation and inflation is unaccounted for.

Step-by-step explanation:

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