Answer:
x=-4.5 or x=-2/9(fraction)
Step-by-step explanation:
3x^2-6x-2=0 simplify so add 3 minus 6 then do ^2
-9x-2=0 Add 2 on both sides
-9x=2 divide by -9 on both sides
x=-4.5 or x=-2/9
First of all, this is not exactly a solvable equation, since you have not told me what you are solving for. However, you can change it into function notation form, or add another equation to create a system.
Answer:
Similarly: you start with an endpoint on both lines to start construction.
Difference: bisector you open the compass to more than half but with congruent you open the compass to the whole length
Step-by-step explanation:
Segment bisector
1. Open a Compass so it's width is more than half the length of the given segment
2. Without changing its width use the compass to draw an arc above and below the given line segment from one of the segment endpoints
3. Again without changing its width use the compass to draw another pair of arcs from the other and points. One arc will be above the segment while the second arc will be below
4. Draw the point of intersection between the pair of arcs below the line segment in between the pair of arcs below the line segment
5. Use a straight edge to connect the intersection points between each pair of arcs
congruent segment
1. Open the compass to it width that matches the given line segment
2. Using a straight edge draw a line that is longer than the given segment was one end point
3. Without changing the width of the compass use the compass to draw an arc on the Ray from its end point
Step 1
The property of a parallelogram is that diagonals of a parallelogram bisect each other and hence have the same midpoint.
This means that the diagonals cut themselves into two equal halves.
Hence, they must have the same mid-points.
Therefore, if we prove that AC and BD have the same midpoint, then ABCD is a parallelogram.
Step 2
Find the midpoint of BD and AC
![\begin{gathered} (\frac{x_2+x_1}{2}),(\frac{y_2+y_1}{2}) \\ BD=(-\frac{1}{2},\frac{9}{2}) \\ AC=(-\frac{1}{2},\frac{9}{2}) \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%28%5Cfrac%7Bx_2%2Bx_1%7D%7B2%7D%29%2C%28%5Cfrac%7By_2%2By_1%7D%7B2%7D%29%20%5C%5C%20BD%3D%28-%5Cfrac%7B1%7D%7B2%7D%2C%5Cfrac%7B9%7D%7B2%7D%29%20%5C%5C%20AC%3D%28-%5Cfrac%7B1%7D%7B2%7D%2C%5Cfrac%7B9%7D%7B2%7D%29%20%5Cend%7Bgathered%7D)
Since they have the same midpoint, the answer will be;
We Prove that AC and BD have the same midpoint which we have done. we know the diagonals of a parallelogram bisect each other; therefore, they have the same midpoint and ABCD is a parallelogram.