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2 years ago

Please help! Find the values of a and b

Mathematics

2 answers:

Leokris [45]2 years ago

6 0

Answer:

a=14

b=6 radical 2

Step-by-step explanation:

45-45-90 rule

Simora [160]2 years ago

5 0

Check the picture below.

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The two right triangles below are similar what is x the missing side length in triangle DEF

sasho [114]

I think that the answer is C. 10

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3 years ago

Given the function f(x) =-2x^2 + 4x -7 find f(-4)

Kamila [148]

Correct the answer is -55

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3 years ago

Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)If the coin is flipped 3 times, what is

Alenkinab [10]

Answer: a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since, its head is twice as likely to occur as its tail.

$p+\dfrac{p}{2}=1\\\\\dfrac{3p}{2}=1\\\\p=\dfrac{2}{3}$

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n = 3

$p=\dfrac{2}{3}$

$q=\dfrac{1}{3}$

Now,

$P(X=1)=^3C_1(\dfrac{2}{3})^1(\dfrac{1}{3})^2=0.2222$

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

$P(X=3)=^5C_3(\dfrac{2}{3})^3(\dfrac{1}{3})^2=0.3292$

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

$P(X\leq 1)=\sum _{x=0}^1^4C_x(\dfrac{2}{3}^x(\dfrac{1}{3})^{4-x}=0.1111$

Hence, a) 0.2222, b) 0.3292, c) 0.1111

8 0

3 years ago

Jadyn prepares a bag of candy before a road trip. The bag contains individual pieces of Skittles, M&Ms, Life Savers and Sour

kipiarov [429]

Given condition is- The bag contains individual pieces of Skittles, M&Ms, Life Savers and Sour Patch Kids.

Let the total number of candies in the bag be = x

Then, Skittles are $\frac{1x}{2}$

Candies left = $x-\frac{x}{2}$ = $\frac{x}{2}$

M&Ms are = $\frac{1x}{8}$

Now remaining candies are= $\frac{3x}{8}$

Now Life savers are = $\frac{9x}{32}$

Now adding all these 3 candies

$\frac{x}{2}+ \frac{x}{8}+\frac{9x}{32}$

= $\frac{29x}{32}$

Now the remaining candies sour patch will be =

$x-\frac{29x}{32} =\frac{3x}{32}$

Hence, sour patch kids are $\frac{3}{32}$

3 0

4 years ago

PLEASE ANSWER ASASP FOR BRAINLEST!!!!!!!!!!!!!!!!!!!!!

kvasek [131]

Answer:

bndflvb

Step-by-step explanation:

5 0

3 years ago