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Olenka [21]
4 years ago
9

circle P has radius 10cm. two perpendicular radii are drawn, and a smaller circle is drawn tangent to both radii and tha larger

circle.  What is the radius of the smaller circle?
Mathematics
2 answers:
Nookie1986 [14]4 years ago
6 0
1/2 of the larger circle
NikAS [45]4 years ago
3 0

Answer: 1/2 of the larger circle

Step-by-step explanation:

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What is four fifths plus eight ninths
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4/5 + 8/9. First we have to find a common denominator for \frac{4}{5} and \frac{8}{9}. \\  \frac{4*9}{5*9}= \frac{36}{45} \ and \  \frac{8*5}{9*5}= \frac{40}{45} \\ Now we are going to add:\frac{36}{45}+ \frac{40}{45}= \frac{76}{45} Make \frac{76}{45} a mixed number:\frac{76}{45}=1 \frac{31}{45} So the answer is \boxed{1 \frac{31}{45}}
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3 years ago
Find r'(t), r(t0), and r'(t0) for the given value of (t0). r(t) = (e^t, e²t), t0 = 0​
creativ13 [48]

Applying the differentiation rule, it can be obtained that:

r'(t)=(e^t,2e^{2t}), r(t_0)=(1,1) and r'(t_0)=(1,2).

<h3>What is the formula for differentiating an exponential function?</h3>

The exponential function exists a mathematical function designated by f(x)=\exp or e^{x}. Unless otherwise determined, the term generally directs to the positive-valued function of a real variable, although it can be extended to complex numerals or generalized to other mathematical objects like matrices or Lie algebras.

In mathematics, the derivative of a function of a real variable estimates the sensitivity to change of the function value affecting a change in its statement. Derivatives exist as a fundamental tool of calculus.

\frac{d}{dt}(e^{mt})=me^{mt}.

Given that r(t)=(e^t,e^{2t}).

So, differentiating r(t)=(e^t,e^{2t}) with respect to t, we get: r'(t)=\left(\frac{d}{dt}(e^t),\frac{d}{dt}(e^{2t})\right).

So, using the above formula \frac{d}{dt}(e^{mt})=me^{mt}, we get: r'(t)=(e^t,2e^{2t}).

Now, substituting t=t_0=0 in r(t)=(e^t,e^{2t}) and r'(t)=(e^t,2e^{2t}), we obtain:

r(t_0=0)=(e^0,e^{2\times 0})=(1,1) and r'(t_0=0)=(e^0,2e^{2\times 0})=(1,2).

Therefore, applying the differentiation rule, we get:

r'(t)=(e^t,2e^{2t}), r(t_0)=(1,1) and r'(t_0)=(1,2).

To know about the differentiation rule, refer:

brainly.com/question/25081524

#SPJ9

5 0
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