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Yuri [45]
3 years ago
6

A sequence of digits has the property that each pair of successive digits, taken in the order written, forms a decimal numeral r

epresenting a multiple of either 1717 or 2323. If the first digit is 99 and the sequence is finite, what is its last (possible) digit
Mathematics
1 answer:
alex41 [277]3 years ago
7 0

Answer:

Concept: Mathematical Sequences

  1. Let An be 99 a double digit multiple
  2. The sequence is finite.
  3. Finite= restricted and not bounded to positive infinity
  4. By that logic the last possible digit is 999999999999999999999999999999999999999999999
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I just learned this topic and have the same question, so I'm not sure if this right. However, I see a fellow student struggling and have to at least put in what I know. My equation was f(n) = 64(1/2)^n-1, then the question was write an expression to represent f(20).

Step-by-step explanation:

So, my answer was f(20) = 64(1/2)^19

f(20) is the number you plug into n. And because the exponent is n-1, I knew to subtract 1 from 20 to get 19.

Then I just wrote the equation out like the original expect with the numbers pluged in: f(20) = 64(1/2)^19

I hope this helps!

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Step-by-step explanation:

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Answer:

After one year the population will be 33 deers, and after two years it will be 36 deers.

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