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Yuri [45]
3 years ago
6

A sequence of digits has the property that each pair of successive digits, taken in the order written, forms a decimal numeral r

epresenting a multiple of either 1717 or 2323. If the first digit is 99 and the sequence is finite, what is its last (possible) digit
Mathematics
1 answer:
alex41 [277]3 years ago
7 0

Answer:

Concept: Mathematical Sequences

  1. Let An be 99 a double digit multiple
  2. The sequence is finite.
  3. Finite= restricted and not bounded to positive infinity
  4. By that logic the last possible digit is 999999999999999999999999999999999999999999999
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bogdanovich [222]
Problem 1)

AC is only perpendicular to EF if angle ADE is 90 degrees

(angle ADE) + (angle DAE) + (angle AED) = 180
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-------------------------------------------------------------

Problem 2)

a) The center is (2,-3) 

The center is (h,k) and we can see that h = 2 and k = -3. It might help to write (x-2)^2+(y+3)^2 = 9 into (x-2)^2+(y-(-3))^2 = 3^3 then compare it to (x-h)^2 + (y-k)^2 = r^2

---------------------

b) The radius is 3 and the diameter is 6

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where
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so, radius = r = 3
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---------------------

c) The graph is shown in the image attachment. It is a circle with center point C = (2,-3) and radius r = 3.

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E = (-1, -3)

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