Answer:
Maggie spent =30
Karen spent = 10
Jasmine spent =20
Step-by-step explanation:
In this we use algebra to solve.we give the sisters unknowns, to help us solve the equation.
we dont know how much jasmine used so we give her the unknown x.you can use any letter but ill us x.
karen used half as much as karen so we give her 1/2x because it was half of jasmine.maggie used 3 times that of karen so w give her 3(1/2x).
maggie =3(1/2x)
Karen =1/2x
jasmine =x
3(1/2x) + 1/2x + x = 60
3/2x + 1/2x + x = 60
2x + x = 60
3x=60
x=20
where we have x =we replace with 20
e.g karen 1/2x => 1/2 x 20 =10
if you need any clarifications please do tell me in the comment section.i would like to help more if you need help.thx
Hope this helps and if it does mark as branliest anwer thx
The graph of the equation y = m^x passes through the point (1, m)
<h3>Equation of a graph</h3>
Given the equation of a graph expressed as y = m^x
We need to determine the coordinate point that lies on this graph.
If x = 1, substitute into the formula to have:
y =m^1
y = m
Hence the required coordinate will be (1, m)
Learn more on equation of graph here: brainly.com/question/24894997
by the double angle identity for sine. Move everything to one side and factor out the cosine term.
Now the zero product property tells us that there are two cases where this is true,
In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of
, so
where
![n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}](https://tex.z-dn.net/?f=n%5B%2Ftex%20%5Dis%20any%20integer.%5C%5CMeanwhile%2C%5C%5C%5Btex%5D10%5Csin%20x-3%3D0%5Cimplies%5Csin%20x%3D%5Cdfrac3%7B10%7D)
which occurs twice in the interval
for
and
. More generally, if you think of
as a point on the unit circle, this occurs whenever
also completes a full revolution about the origin. This means for any integer
, the general solution in this case would be
and
.
Answer:
Do you have the a picture of the table
Answer:
Step-by-step explanation:
8/3 = 2.6666 (repeating 6)
so rounded about 2.7 minutes per lap :)
