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4 years ago

7

Identify the 25th term of the arithmetic sequence 2, 1 and 3 over 5,

2 answers:

Katarina [22]4 years ago

5 0

-7 3/5 is the correct answer simplified.

raketka [301]4 years ago

3 0

First, you have to transform your numbers into proper fractions:
1 and 3/5 = (5+3)/5 = 8/5
1 and 1/5 = (5+1)/5 = 6/5

Therefore your arithmetic sequence is 2, 8/5, 6/5, ...

In an arithmetic sequence, the difference between a given term and the preceding one is equal to the difference between the <span>following </span>term and the given one. In your case:
d = 8/5 - 2 = (8-10)/5 = -2/5
As a prove: d = 6/5 - 8/5 = -2/5

Now, in order to find the 25th term you need to apply the formula:
an = a + (n - 1)d
where an is the number you are looking for, a is the first term, n is the term you are looking for and d is the distance.
Hence,
a₂₅ = 2 + (25-1)(-2/5) = 2 - 24·2/5 = 2 - 48/5 = (10-48)/5 = -38/5

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Yuri [45]

$\implies {\blue {\boxed {\boxed {\purple {\sf { \: A. \:- 8 {v}^{4} + 3 {v}^{3} + v + 5}}}}}}$

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7 0

3 years ago

9.75t + 9 = 18.5t + 16

Lana71 [14]

Answer:

the answer is to your equation is t=-0.8

3 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B2x%2B4%7D%7Bx%5E%7B2%7D-2x-8%20%7D" id="TexFormula1" title="\frac{2x+4}{x^{2}-2x-8 }

lisabon 2012 [21]

Answer:

$\frac{2}{x-4}$

Step-by-step explanation:

$\frac{2x+4}{x^2-2x-8}$

Factor both the numerator and denominator

$\frac{2(x+2)}{(x-4)(x+2)}$

The $x+2$ 's cancel out

The equation in its simplest form is $\frac{2}{x-4}$

Hope this helps!

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3 years ago

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larisa [96]

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3 years ago

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SIZIF [17.4K]

Answer:

The top graph

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-2

0

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