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3 years ago

8

2.36 to the nearest whole number

2 answers:

Igoryamba3 years ago

7 0

Answer:

2

Step-by-step explanation:

2.36 would need to be at least 2.50 or higher to be rounded to 3 so we round down to 2

hope this helps <3

jolli1 [7]3 years ago

7 0

THE ANSWER IS 2

explanation:
2.3 is closer to 2 than 3
also, because
THIS PLACE ABOUT TO BLOWWWWWWWWW OH OH OH OH OH OHHHHHHHHHHHHHH

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Common core question please help!!!

Maru [420]

She has 648 shirts.

Work:
Lisa has 42 pineapples. 4 + 2 = 6
Johnny has 6 marbles.
42 + 4 + 2 + 6 = 54
54 + 5 + 4 = 63
63 + 6 + 3 = 72
But 72 is a multiple of 6!
Let's go further:
72 * 6 = 432

Now let's look at the word 'shirt'.
The middle letter is I.
I is the 9th letter of the alphabet.
Remember the number 72?
72*9 = 648

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3 years ago

Using the order of operations, what is the last calculation that should be done to evaluate

mel-nik [20]

200-(-2) is actually 200-1(-2)

So thats multiplication

Then its 200+2

So addition is the last calculation to be done.

7 0

3 years ago

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Help im still lazy lol

jonny [76]

Answer:

t=-105

Step-by-step explanation:

$-\frac{1}{15} t =7$

What we need to do here is to isolate t.

Let's multiply both sides by -15.

$-\frac{1}{15}t * -15 = 1t$

7*-15= -105

t=-105

6 0

3 years ago

Read 2 more answers

15 POINTS FOR AN EASY QUESTION!!!

Rainbow [258]

Your answer is C. 6.5!
If you need steps just tell me!
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4 years ago

Read 2 more answers

If 28% of students in College are near-sighted, the probability that in a randomly chosen group of 20 College students, exactly

cluponka [151]

Answer: (D) 16%

Step-by-step explanation:

Binomial probability formula :-

$P(x)=^nC_xp^x(1-p)^n-x$ , where n is the sample size , p is population proportion and P(x) is the probability of getting success in x trial.

Given : The proportion of students in College are near-sighted : p= 0.28

Sample size : n= 20

Then, the the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is given by :_

$P(x=4)=^{20}C_4(0.28)^4(1-0.28)^{20-4}\\\\=\dfrac{20!}{4!16!}(0.28)^4(0.72)^{16}\\\\=0.155326604912\approx0.16\%$

Hence, the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is closest to 16%.

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3 years ago