The price of Ravi's lunch, before tax and tip was added to the total cost of the meal is $13.19.
<h3>What is the price of the lunch?</h3>
Both the tax and the tip paid would increase the cost of the meal. Thus, their dollar value has to be subtracted from the total amount he pays.
Value of the lunch after the tip has been removed = (1 - 0.2) x 17.92 = $14.34
Value of the lunch after the tax has been removed = (1 - 0.08) x $14.34 = $13.19
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Answer:
To solve an exponential equation, take the log of both sides, and solve for the variable.
Step-by-step explanation:
Example 1: Solve for x in the equation tex2html_wrap_inline119 .
Solution:
Step 1: Take the natural log of both sides:
displaymath121
Step 2: Simplify the left side of the above equation using Logarithmic Rule 3:
displaymath123
Step 3: Simplify the left side of the above equation: Since Ln(e)=1, the equation reads
displaymath127
Ln(80) is the exact answer and x=4.38202663467 is an approximate answer because we have rounded the value of Ln(80)..
Check: Check your answer in the original equation.
displaymath131
Answer:
B
Step-by-step explanation:
Edge
Answer:
7 is in thousands place and its place value is 7000, 2 is in hundreds place and its place value is 200, 6 is in ten place and its place value is 60, 3 is in ones place and its place value is 3.
0, 1, 2, 3, 4, 5, 6, 7, 8, 9. The place value of a 3-digit number helps in understanding the value of each of the digits. The smallest of 3-digit numbers is 100 and the largest number is 999.
Step-by-step explanation:
For the first one, you did good. I will just suggest a couple things.
Statement Reason
JK ≅ LM Given
<JKM ≅ < LMK Given (You did both of these steps so well done.)
MK ≅ MK Reflexive Property (Your angle pair is congruent but isn't one of the interior angle of the triangles you are trying to prove.)
ΔJMK ≅ ΔLKM SAS
Problem 2: (You also have a lot of great stuff here.)
Statement Reason
DE ║ FG Given
DE ≅ FG Given
<DEF≅<FGH Given
<EDF≅<GFH Corresponding Angles (You don't need to know that F is the midpoint but you got corresponding angle pair which is correct.)
ΔEDF≅ΔGFH ASA
<DFE≅<FHG CPCTC
