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horrorfan [7]
2 years ago
12

Algebra 1 Honors Add Polynomials to find perimeter​

Mathematics
1 answer:
Anit [1.1K]2 years ago
3 0

Answer:

4z-16 units

Step-by-step explanation:

P=4S

S=z-4

P=4(z-4)

P=4z-16

The perimeter of the rectangle is 4z-16 units.

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The janitor found that it was leaking at a rate of 3 fl oz per minute.How fast was the pipe leaking in gallons per hour?
SSSSS [86.1K]

Answer:

First, you would have to convert fl oz to gallons: 1 fl oz = 0.0078125 gal. Therefore, 4 fl oz = 0.03125 gal.

Then, you would have to convert minutes to hours: 1 minute = 0.01666 hours, or 60 minutes = 1 hour.

From here, you can divide 0.03125 gal by 0.01666 hours OR multiply 0.03125 gal by 60 minutes, giving a rate of 1.87 gallons per hour.

5 0
2 years ago
X2–6x + 10 is to be written in the form ( x +a)2+ b Find the values of a and b.
vampirchik [111]

Answer:

a = -3 and b = 1

Step-by-step explanation:

x² - 6x + 10

→ Half the second term and place it in the bracket

( x - 3 )²

→ Square -3

- ( 3 )² = -9

→ Place this outside the brackets along with plus 10

( x - 3 ) ² - 9 + 10

→ Simplify

( x - 3 ) ² + 1

8 0
2 years ago
HELP PLEASE!!
Taya2010 [7]

Answer:

A customer inside a store slips in a pool of water and injures his back.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Electron groups could be considered which of the following?
Yanka [14]
Im pretty sure D bonded pair of electrons is the answer
6 0
2 years ago
When finding​ percentiles, if the locator L is not a whole​ number, one procedure is to interpolate so that a locator of​ 23.75,
inessss [21]

Answer:

The answer is "94"

Step-by-step explanation:

Given data:

51,54,64,68,72,74,76,83,94,94,99

Find:

P_{75}=?P_{75}= (\frac{75(n+1)}{100})^{th} \ \ observation\\\\

      = (\frac{75(11+1)}{100})^{th} \ \ observation\\\\= (\frac{75(12)}{100})^{th} \ \ observation\\\\= (\frac{75 \times 12}{100})^{th} \ \ observation\\\\= (\frac{900}{100})^{th} \ \ observation\\\\= 9^{th} \ \ observation\\\\= 9^{th} \ number \ is = 94

7 0
3 years ago
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