Answer:
2, 0, 2, 3, 5
1, 2, 4, 0, 5
Step-by-step explanation:
(ax + b)(cx² + dx + e)
acx³ + adx² + aex + bcx² + bdx + be
2(2)x³ + 2(3)x² + 2(5)x + 0 + 0 + 0
4x³ + 6x² + 10x
a = 2
b = 0
c = 2
d = 3
e = 5
1(4)x³ + 1(0)x² + 1(10)x + 2(4)x² + 0 + 10
4x³ + 8x² + 10x + 10
a = 1
b = 2
c = 4
d = 0
e = 5
Step-by-step explanation:
3(-8m-1) + 5(m+8) (remove the parentheses)
-24m - 3 + 5m + 40 (collect like terms and calculate)
-19m + 37
Answer:
2<x<8
Here is the answer to he above question you asked. (I have to type at least 20 words to post my answer...)
Answer:
If point C lies between two points A and B such that AC=BC, then point C is the bisector of A and B, that means it is at right the centre.
Answer:
1st box: (-5,-2)
2nd box: up and down
3rd box: 8
4th box: +-4/3
5th box: y+2 = +-4/3 (x+ 5)
Step-by-step explanation:
Just took the k12 unit test, hope this helps!
