The set when z = -5 is {-27, -9, -5}
<h3>How to determine the set elements?</h3>
The set is given as:
{(4z-7,z-4,z) |z is any real number}
When z=-5, we have:
4z - 7 = 4(-5) - 7 = -27
z - 4 = -5 - 4 = -9
z = -5
So, we have:
{(4z-7,z-4,z) |z is any real number} ⇒ {-27, -9, -5}
Hence, the set when z = -5 is {-27, -9, -5}
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Answer:
D. (8,0), (4,0)
Step-by-step explanation:
they both on tha line
Answer:
D. (0, 3)
Step-by-step explanation:
Remember you can do anything to an equation as long as you do it to both sides
17-9x=-3+16x
add 9x to both sides
17=-3+25x
add 3 to both sides
20=25x
divide both sides by 25
Answer:
x=1
Step-by-step explanation:
Add 3 to both sides
6x=3+3
Simplify 3 + 3 to 6
6x=6
Divide both sides by 6
x=1