Answer:
The number of miles Mark runs in each track be ![16 \frac{43}{52}\ miles](https://tex.z-dn.net/?f=16%20%5Cfrac%7B43%7D%7B52%7D%5C%20miles)
Step-by-step explanation:
Let us assume that the number of miles Mark run in each track meet be x.
As given
Mark ran 875 miles this year in the track club.
Mark ran in 52 track meets and ran the same number of miles in each.
Than the equation becomes
52 × x = 875
![x = \frac{875}{52}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B875%7D%7B52%7D)
![x = 16 \frac{43}{52}\ miles](https://tex.z-dn.net/?f=x%20%3D%2016%20%5Cfrac%7B43%7D%7B52%7D%5C%20miles)
Therefore the number of miles Mark runs in each track be ![16 \frac{43}{52}\ miles](https://tex.z-dn.net/?f=16%20%5Cfrac%7B43%7D%7B52%7D%5C%20miles)
Answer:
D,B,A,
Step-by-step explanation:
Hope that helped
Answer:
Step-by-step explanation:
If (x + 2) is a factor of a polynomial then ( - 2 ) is the zero of that polynomial ⇒ ( - 2 )³ + 2( - 2 )² + 2( - 2 ) + k = 0 ⇒ k = - 4
Answer:
34
Step-by-step explanation:
(10)(4)−(4)(3)−2x−6x+8+(−3)(4)+(6)(3)−(2)(2)+8x−4
= 40+−12+−2x+−6x+8+−12+18+−4+8x+−4
Combine like terms:
= 40+−12+−2x+−6x+8+−12+18+−4+8x+−4
= (−2x+−6x+8x)+(40+−12+8+−12+18+−4+−4)
= 34
This is done by solving the question using the linear equation. If x=0 then y = -43,886 udring the year 1900. If x=88, then y=1698. The difference between the observed value and tthe predicted value at the value of x is 42,188.