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eduard
3 years ago
5

PLEASE HELP WILL MARK BRAINEST

Mathematics
2 answers:
Vinil7 [7]3 years ago
7 0
What do you need help with ?
LenaWriter [7]3 years ago
3 0
Why do u need help with?
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Put the following fractions in order from greatest to least:
7nadin3 [17]

Answer:

greatest to least

c) c, d, b, a

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3 years ago
What are data sorted into before they are plot as a histogram
Olin [163]

Answer:

use google lol

use google lol

8 0
3 years ago
What is the measure of angle 1?
Ronch [10]

Answer:

92°

Step-by-step explanation:

because 1 is parallel to the 92°

5 0
3 years ago
Read 2 more answers
The endpoints of segment RS are R(-4, 3) and S(8, -5). Complete each statement using a fraction.
Ray Of Light [21]

Answer:

a. (-1 , 1) is the point at 1 : 3 of the way from R to S

b. (5 , -3) is the point at 3 : 1 of the way from R to S

Step-by-step explanation:

* Lets explain how to solve the problem

- If point (x , y) divide a line segment whose end points are

 (x_{1},y_{1}) and (x_{2},y_{2}), at ratio

 m_{1}:m_{2} from the first point, then

 x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}} and

 y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}

* Lets solve the problem

a.

∵ RS is a line segment whose end points are R (-4 , 3) and S (8 , -5)

∵ Point (-1 , 1) divides it at ratio m_{1}:m_{2} from R

- By using the rule above

∴ -1=\frac{-4m_{2}+8m_{1}}{m_{1}+m_{2}}

- By using cross multiplication

∴ (-1)m_{1}+(-1)m_{2} = -4m_{2}+8m_{1}

- By collecting m_{1} in one side and m_{2} in the

 other side

∴ 3m_{2}=9m_{1}

- Divide both sides by 3

∴ m_{2}=3m_{1}

∴ m_{1}=\frac{1}{3}m_{2}

∴ (-1 , 1) is the point at 1 : 3 of the way from R to S

b.

∵ RS is a line segment whose end points are R (-4 , 3) and S (8 , -5)

∵ Point (5 , -3) divides it at ratio m_{1}:m_{2} from R

- By using the rule above

∴ 5=\frac{-4m_{2}+8m_{1}}{m_{1}+m_{2}}

- By using cross multiplication

∴ 5m_{1}+5m_{2} = -4m_{2}+8m_{1}

- By collecting m_{1} in one side and m_{2} in the

 other side

∴ 9m_{2}=3m_{1}

- Divide both sides by 3

∴ 3m_{2}=m_{1}

∴ \frac{m_{1}}{m_{2}}=3

∴ (5 , -3) is the point at 3 : 1 of the way from R to S

8 0
4 years ago
The radius of the circle x^2+y^2 +px+6y-3=0 is 4. find the possible values of p​
worty [1.4K]

Here, the given equation is,

x^2+y^2+px+6y-3=0

By copairing it with x^2+y^2+2gx+2fy+c=0, we get,

2g=p or, g=p/2

2f=6 or, f=3

c=-3

now the radius is,

r^2=g^2+f^2-c

or, 4^2=(p/2)^2 +3^2 -(-3)

or, 16= p^2/4 +9+3

or, 16-9-3=p^2/4

or p^2/4=4

or, p^2=4×4

or p^2=4^2

or p=4

therefore the rewuired value of p is 4.

6 0
3 years ago
Read 2 more answers
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