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FrozenT [24]
3 years ago
9

Convert (76)10 into Binary.​

Chemistry
1 answer:
Vlada [557]3 years ago
6 0

Answer:

The base-10 value of 76(10 )

is equal to base-2 value of 10011002.

Explanation:

Step 1) Divide 76 by 2 to get the Quotient. Keep the Whole part for the next step and set the Remainder aside.

Step 2) Divide the Whole part of the Quotient from Step 1 by 2. Again, keep the Whole part and set the Remainder aside.

Step 3) Repeat Step 2 above until the Whole part is 0.

Step 4) Write down the Remainders in reverse order to get the answer to 76 as a binary.

Here we will show our work so you can follow along:

76 / 2 = 38 with 0 remainder

38 / 2 = 19 with 0 remainder

19 / 2 = 9 with 1 remainder

9 / 2 = 4 with 1 remainder

4 / 2 = 2 with 0 remainder

2 / 2 = 1 with 0 remainder

1 / 2 = 0 with 1 remainder

Then, when we put the remainders together in reverse order, we get the answer. The decimal number 76 converted to binary is therefore:

1001100

Pls mark me as brainliest I am in need

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<u>Answer:</u>

For 1: The correct answer is 407.97 grams.

For 2: The correct answer is 76.72 grams.

<u>Explanation:</u>

  • <u>For 1:</u>

We are given the molarity of HCl, to find the moles of HCl, we use the formula:

Molarity=\frac{\text{Moles}{\text{Volume}}

We are given:

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Putting values in above equation, we get:

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By Stoichiometry of the reaction:

2 moles of HCl reacts with 1 mole of zinc metal.

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To calculate the mass of zinc metal, we use the formula:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}    .....(1)

Molar mass of Zinc metal = 65.38 g/mol

6.24=\frac{\text{Mass of zinc metal}}{65.38g/mol}\\\\\text{Mass of zinc metal}=407.97g

  • <u>For 2:</u>

We are given that 298 grams of 83.1 % by mass of iron (II) nitrate solution are present.

So, mass of Iron (II) nitrate solution will be = \frac{83.1}{100}\times 298=247.638g

Molar mass Iron (II) nitrate = 180 g/mol

Putting values in equation 1, we get:

\text{Moles of }Fe(NO_3)_2=\frac{247.638g}{180g/mol}=1.37mol

For the following reaction:

2Al(s)+3Fe(NO_3)_2(aq.)\rightarrow 3Fe(s)+2Al(NO_3)_3(aq.)

By Stoichiometry of the reaction:

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So, 1.37 moles of Fe(NO_3)_2 will produce = \frac{3}{3}\times 1.37=1.37mol of iron metal.

To calculate the mass of zinc metal, we equation 1:

1.37=\frac{\text{Mass of iron metal}}{56g/mol}\\\\\text{Mass of iron metal}=76.72g

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