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Lina20 [59]
3 years ago
7

Thalium-208 has a half-life of 3 minutes. If the initial amount was 100 mg, how much of the Thalium-208 will remain after 14 min

utes?
Mathematics
2 answers:
-BARSIC- [3]3 years ago
8 0

Answer:

1.0mg

Step-by-step explanation:

7nadin3 [17]3 years ago
4 0

Answer:

Step-by-step explanation:

if

You might be interested in
Nineteen immigrants to the U.S. were asked how many years, to the nearest year, they have lived in the U.S. The data are as foll
JulsSmile [24]

Answer:

a) The frequency of the data "<em>15</em>" and "<em>20</em>" is 2 for both, not 1; this means their relative frequency is 2/19 for both, not 1/19; finally, the cumulative relative frequency in the row of the data "15" should be 0.8947, not 0.8421. This error might have happened because someone didn't count the numbers correctly, so they only noticed one "15" and one "20" when, in fact, there were two people that had lived in the U.S. for 15 years, and two more people for 20 years. On the other hand, the error in the cumulative relative frequency happened because it accounted for only one person living in the U.S. for 15 years, instead of two people.

b) Roughly 47% of the people surveyed have lived in the U.S. from 0 to 5 years, <em>not </em>for 5 years. The cumulative relative frequency in this row (47%) accounts for every data gathered so far, not just the "5 years" row. The correct statement would be that <em>3 out of 19</em>, or 15.8% (relative frequency) of the people surveyed have lived in the U.S. for 5 years.

Step-by-step explanation:

1) First of all, to avoid errors like the one in the problem's table, <em>we should first place the given numbers from least to greatest</em>, so we can construct a new frequency table by ourselves. Let's do just that, and we'll end up with something like this:

0 , 0, 2 , 2, 2, 4, 5, 5, 5, 7, 7, 10, 10, 12, 12 , 15, 15, 20, 20

Now we'll have a much easier time from now on.

2) The second step is to <em>construct the Data and Frequency columns</em>. Just place each unique integer in a new row of the <em>Data </em>column, then count how many times that unique integer was found, and, finally, place that number below the <em>Frequency </em>column (<em>Please refer to the Excel Worksheet provided as an attachment). </em>

Let's do it as follows:

Data     Frequency

0            2

2            3

4            1

5            3

7            2

10           2

12           2

15           2

20          2

<em>Note that we counted "15" and "20" twice! So each one of those rows have a frequency of 2, not 1 as the table presented in the problem suggests. </em>

3) Next, we want to construct the Relative frequency and Cumulative relative frequency columns. For the relative frequency column, <em>we just divide the frequency of each row by the total number of immigrants surveyed, which is 19</em>. For the cumulative relative frequency column, <em>we will get each row's relative frequency, and add the cumulative relative frequency of the row before it</em>. Note that for the first row, the cumulative relative frequency is the same as its relative frequency.

We should get something like this:

Data    Frequency    Relative frequency    Cumulative relative frequency

0            2                   2/19                               0.1053

2            3                   3/19                               0.2632

4            1                    1/19                                0.3158

5            3                   3/19                               0.4737

7            2                   2/19                               0.5789

10           2                   2/19                               0.6842

12           2                   2/19                               0.7895

15           2                   2/19                               0.8947

20          2                   2/19                               1.0000

<em>Note that the relative frequency for both "15" and "20" is 2/19 instead of 1/19! Also, we got a cumulative relative frequency of 0.8947 in the row of "15", instead of 0.8421.</em>

4) a) We have just fixed the error in the table, but we have to <em>explain how someone might have arrived at the incorrect number(s)</em>. The most logical way that someone might have gotten the incorrect frequencies of "15" and "20" is that <em>they didn't count the numbers correctly while building the Frequency column</em>. This could have happened because <em>that person probably didn't order the numbers from least to greatest</em>, as we did in Step 1, which makes it way easier to get the frequency of each data without making a mistake.

5) b) We have now to <em>explain what is wrong with the statement "47% of the people surveyed have lived in the U.S. for 5 years</em>.

To answer that, we can refer to the relative frequency of the row of the data "5", which tells us that 3 out of 19 (or roughly 15.8%) of the people surveyed have lived in the U.S. for 5 years. <em>Relative frequency is telling us the percentage of people that have lived for </em><em>this </em><em>amount of time.</em>

By contrast, <em>the cumulative relative frequency of this same row tells us that </em>0.4737, or roughly 47%, of the people surveyed have lived for 5 years or less. Cumulative relative frequency accounts for the data presented in its row, <em>plus </em>the data presented in the rows before it.

So the correct statement would be either:

  • 15.8% of the people surveyed have lived in the U.S. for 5 years, or
  • Roughly 47% of the people surveyed have lived in the U.S. for 5 years or less.
Download xlsx
7 0
4 years ago
A system with 6 independent components is such that the system will fail if at least one of the individual components fail. the
Ipatiy [6.2K]
The components operate independently, so the probability of "total" system failure is the same as the product of each probability of component failure. That is, if A_i denotes the event that component i fails, then

\mathbb P(A)=\mathbb P(A_1\cup\cdots\cup A_6)=\mathbb P(A_1)\times\cdots\times\mathbb P(A_6)

The A_i are independent and identically distributed, so \mathbb P(A_i)=\mathbb P(A_j) for all i,j. So

\mathbb P(A)=\mathbb P(A_1)^6=0.02^6=6.4\times10^{-11}=0.000000000064
7 0
3 years ago
What is the solution to the system of equations? (7, 4) (7, startfraction 13 over 3 endfraction) (8, startfraction 14 over 3 end
miss Akunina [59]

The points are (7, 13/3).

Lets simplify the equation,

The equation of first line: y = 1/3 x + 2

the equation of second line: y= 4/3x - 5

Solve the system of equations by elimination,

Multiply equation A by -4 both sides

-4y = -4(1/3x +2)

-4y = -4/3x-8

After eliminating the equation we get,

y = 13/3

So now have to find x

13/3 = 1/3x + 2

Lets multiply above by 3
x = 13-6

x = 7.

Hence the points are (7, 13/3)

Learn more about Quadratic Equation on:

brainly.com/question/1214333

#SPJ4

5 0
2 years ago
7b-2/5=6b-7/5 nudfghnkdfbvugyteugdyvbbbvybhjedfs
sveta [45]

Answer:

b=−1

Step-by-step explanation:

4 0
3 years ago
Which has no factors other than 1 and itself?
amid [387]

Answer:

79

Step-by-step explanation:

there are no other factors  everything else can factor in 5 or 3

8 0
3 years ago
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