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belka [17]
3 years ago
7

You have a shuffled deck of three cards: 2, 3, 4. You draw one card. Let C_i denote the event that the card i is picked. Let E d

enote the event that the card chosen is an even-numbered card. a. What is P[C_2|E], the probability that the 2 is chosen given that an even-numbered card is chosen? b. What is the conditional probability that an even-numbered card is picked given that a 2 is picked?
Mathematics
1 answer:
Goshia [24]3 years ago
7 0

Answer:

a) 0.5

b) 1  

Step-by-step explanation:

We are given the following in the question:

We have a deck of 3 cards: 2, 3, 4.

C_i: card i is picked.

E: card chosen is an even-numbered card.

Definition:

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

P(C_i) = \dfrac{1}{3}\\\\P(E) = \dfrac{2}{3}

P(C_2) = \dfrac{1}{3}

a) probability that the 2 is chosen given that an even-numbered card is chosen

P(C_2|E)\\\\=\dfrac{P(C_2)\cap P(E)}{P(E)}\\\\=\dfrac{\frac{1}{3}}{\frac{2}{3}}=\dfrac{1}{2}

b) conditional probability that an even-numbered card is picked given that a 2 is picked

P(E|C_2)\\\\=\dfrac{P(E)\cap P(C_2)}{P(C_2)}\\\\= \dfrac{\frac{1}{3}}{\frac{1}{3}} = 1

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Find number a and k so that x-2 is afactor<br>OF F(x)=x4-2ax tax-<br>X+k and F(-1)=3​
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Find numbers a and k so that x-2 is a factor of

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Step-by-step explanation:

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f(x)=x^4-2ax^3+ax^2- x+k

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