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1 year ago

Rewrite the equation in Ax+By=C form. Use integers for A, B, and C. y+1=2(x+5)

Mathematics

1 answer:

musickatia [10]1 year ago

3 0

Step-by-step explanation:

y + 1 = 2(x + 5) = 2x + 10

y - 9 = 2x

2x - y = -9

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Factor completely: 2x4 − 32.

vazorg [7]

Answer:

Option b) is correct.

The completed factor of given expression is $2(x-2)(x+2)(x^2+4)$

Step-by-step explanation:

Given expression is $2x^4-32$

To find the completed factor for the given expression:

$2x^4-32$ :

Taking the common number "2" outside to the above expression we get

$2x^4-32=2(x^4-16)$

Now rewritting the above expression as below

$=2(x^4-2^4)$ (since 16 can be written as the number 2 to the power of 4)

$=2((x^2)^2-(2^2)^2)$

The above expression is of the form $a^2-b^2=(a+b)(a-b)$

Here $a=x^2$ and $b=2^2$

Therefore it becomes

$=2(x^2+2^2)(x^2-2^2)$

$=2(x^2+4)(x^2-2^2)$

The above expression is of the form $a^2-b^2=(a+b)(a-b)$

Here $a=x$ and $b=2$

Therefore it becomes

$=2(x^2+4)(x+2)(x-2)$

$=2(x+2)(x-2)(x^2+4)$

Therefore $=2(x+2)(x-2)(x^2+4)$

$2x^4-32=2(x-2)(x+2)(x^2+4)$

Option b) is correct.

The completed factor of given expression is $2(x-2)(x+2)(x^2+4)$

3 0

3 years ago

Read 2 more answers

Help me please will be appreciated thx

alexandr1967 [171]

Answer:

-6 +8d -2c

Step-by-step explanation:

$\frac{-2}{5} (15 -20d +5c) = \frac{-2}{5} \times 15 - \frac{-2}{5}\times20d +\frac{-2}{5}\times5c = -6 + 8d -2c$

3 0

2 years ago

Slope of the line<br> (5,11) (-5,-1)

AnnZ [28]

Answer:

1.8

Step-by-step explanation:

To do this, you need the slope formula

y^2 - y^1 over

x^2 - x^1

x^1 y^2 x^2 x^1

( 5, 11) (-5 -1)

-7 - 11 = -18

-5 -5 = -10 (divide) = 1.8

4 0

3 years ago

Read 2 more answers

Xinran walks 3 mi/h uphill, 4 mi/h on flat land and 5 mi/h downhill. If he walks one mile uphill, then one mile on flat land and

Dmitriy789 [7]

Given :

Xinran walks 3 mi/h uphill, 4 mi/h on flat land and 5 mi/h downhill.

To Find :

If he walks one mile uphill, then one mile on flat land and then returns by the same route to his starting point, how many minutes does he walk.

Solution :

Time taken to walk one mile uphill is :

$t_1 = \dfrac{1}{3}\ hours$

Time taken to walk two mile on flat land( one on going and one or returning ) is :

$t_2 = \dfrac{2}{4}\ hours\\\\ t_2 = \dfrac{1}{2}\ hours$

Time taken to walk one mile downhill is :

$t_3 = \dfrac{1}{5}\ hours$

Total time taken :

$T = t_1 + t_2 + t_3 \\\\T = \dfrac{1}{3} + \dfrac{1}{2}+\dfrac{1}{5}\\\\T = \dfrac{10 + 15 + 6}{30} \\\\T = \dfrac{31}{30}\ hours = \dfrac{31}{30}\times 60 \ minutes\\\\T = 62\ minutes$

Therefore, time taken un 62 minutes.

7 0

3 years ago

Find the value of this expression if x = 4.<br> X^2-8 / x-6

Misha Larkins [42]

Answer:

the answer is -4

Step-by-step explanation:

x^2 is 16

16-8=8 for the numerator

4-6= -2 for the denominator

so, 8/(-2)= -4

5 0

3 years ago