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podryga [215]
3 years ago
15

In the ground state, all of the atoms of Period 3 elements have the same

Chemistry
1 answer:
Ksivusya [100]3 years ago
3 0

Answer:

Shell number

Explanation:

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O2+CS2-----> CO2+SO2
jonny [76]

3 O2 + CS2 = CO2 + 2 SO2            

That is the balanced equation!

I may be late lol!!

Hope it helps


3 0
3 years ago
PLEASE HELP!!! URGENT!!! WILL MARK BRAINLIEST
seraphim [82]
<h2>A  sample of gold (Au) has a mass of 72.04g. Calculate the number of atoms of gold (Au): It is equal to ==2.207 x 10²³ number of atoms </h2>

Explanation:

we can find number of atoms in a given sample by the formula :

Number of atoms = Given mass /atomic mass  x Avogadro's number

or , it can be written as :

Number of atoms = given mass /atomic mass x 6.022 x 10²³

Now in above asked question , the values given are :

Mass of sample of gold = 72.04g

Atomic mass of gold : 196.6

Avogadro's number = 6.023 x 10²³

so, using the above formula we have :

Number of atoms = 72.04 /196.6 x 6.022 x 10²³

= 0.3664 x 6.022 x 10²³

=2.207 x 10²³ number of atoms

8 0
3 years ago
What is the difference between atomic mass and number?
OlgaM077 [116]
Atomic mass is the number of protons and neutrons in an element while an atomic number is the number of protons in the element.
5 0
3 years ago
What is the molarity of a solution of KNO3 (molecular mass = 101) that contains 404 grams of KNO3 in 2.00 liters of solution? A.
ss7ja [257]

Answer:2.00

Explanation:

3 0
3 years ago
If a 58 g sample of metal at 100 c is placed into calorimeter containing 60g of water at 18 c , the temperature of the water inc
tatiyna

Answer:

The water will absorb 1004.16 Joule of heat

Explanation:

Step 1: Data given

Mass of the metal = 58.00 grams

Temperature of the metal = 100.00 °C

Mass of water = 60.00 grams

Temperature of water = 18.00 °C

Final temperature = 22.00 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculate the amount of heat absorbed by the water in joules

Q = mass *specific heat *ΔT

 ⇒ with Q = the heat absorbed by water

⇒ with mass of water = 60.00 grams

⇒ with specific heat of water = 4.184 J/g°C

⇒ with ΔT = The change in temperature of water = T2 - T1 = 22 - 18 = 4.0 °C

Q = 60.00 * 4.184 J/g°C * 4.0 °C

Q = 1004.16 J

The water will absorb 1004.16 Joule of heat

6 0
3 years ago
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