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sleet_krkn [62]
3 years ago
5

After Rutherford bombarded gold foil with alpha particles, he concluded that the volume of an atom is mostly empty space. Which

observation led Rutherford to this conclusion?
1. Some of the alpha particles were deflected 180 degrees
2. The paths of deflected alpha particles were hyperbolic.
3. Many alpha particles were absorbed by gold nuclei.
4. Most of the alpha particles were not deflected.
Chemistry
2 answers:
marta [7]3 years ago
5 0

Answer: 4. Most of the alpha particles were not deflected.

Explanation:

Rutherford gave an experiment known as gold foil experiment.

In his experiment, he took a gold foil and bombarded it with alpha particles (carrying positive charge). He thought that the particles will pass straight through the foil, but to his surprise, many of them passed through, some of them deflected their path and a few of them bounced back.

Due to the presence of positive charge on the alpha particles they must be deflected, but as there exists a large empty space as most of the alpha particles pass through without deflection.  

irina [24]3 years ago
4 0
4)
Because if it doesn't deflect in the middle it means that there has to be some space for the alpha particles to go through it. 
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According to the bohr model, what determines the shortest wavelength in a given series of wavelengths emitted by the atom?
algol13

According to the bohr model "The lower energy level into which the electron deflects from a higher energy level is designated by the quantum number nf" determines the shortest wavelength in a given series of wavelengths emitted by the atom.

By explaining that electrons move in fixed orbitals (shells) and not anywhere in between, Bohr theory amended the atomic structure model.

He also showed that each orbit (shell) has a fixed energy. Bohr refined Rutherford's model of the atom's nucleus to include electrons and their varying energy levels.

According to Rydberg formula

1/λ = R [1/ni² - 1/nf²]

λ = wavelength

R = Rydberg constant

ni & nf are integers or principal quantum numbers where nf > ni

So if we want wavelength(λ) to be shortest, then 1/nf should be zero.

In this way , it depends on nf and not on ni

That's why the lower energy level into which the electron deflects from a higher energy level is designated by the quantum number nf" determines the shortest wavelength in a given series of wavelengths emitted by the atom.

Learn more about Bohr's model here brainly.com/question/18002213

#SPJ4

4 0
2 years ago
A 2.10g of unknown monoprotic acid is titrated with 38.10 mL of .265M NaOH. Calculate the molar mass of the ac? I already calcul
Shkiper50 [21]
V_{NaOH}=38,1mL=0,0381L\\
C_{m}=0,265M\\\\
n=C_{m}*V=0,265\frac{mol}{L}*0,0381L\approx0,0101mol

HR    +      NaOH ⇒ NaR + H₂O
1mol   :     1mol

0,0101mol \ \ \ \ \Rightarrow \ \ \  \ 2,1g\\
1mol  \ \ \ \ \ \ \ \ \ \ \Rightarrow \ \ \ m\\\\
m=\frac{1mol*2,1g}{0,0101mol}\approx 207,92g\\\\
M_{HR}=207,92\frac{g}{mol}
5 0
3 years ago
Calculate the ph of a solution obtained by mixing 100ml each of 0.1M HCL, 0.1M HNO3 and 0.1M NaOH solutions.
Volgvan
Given:

Volume of each of the solutions = 100 mL of each
Concentration of HCl = 0.10 M
Concentration of HNO3 = 0.10 M
Concentration of NaOH = 0.10 M

If all are mixed in one solution, the pH will surely be low since there are two acids mixed with one base. The pH range should be 1 - 5. <span />
7 0
3 years ago
Margarine is usually made by a process called ________, in which hydrogen atoms are added to unsaturated fatty acids found in ve
Butoxors [25]
Saturation, this is where all the octets are filled with hydrogens
3 0
3 years ago
Vinegar is a commercial form of acetic acid, HC2H3O2 (aq). One sample vinegar has a pH value of 2.4. State the pH value of a sam
Yuri [45]

3.41 is  the pH value of a sample that has ten times fewer hydronium ions than an equal volume of a vinegar sample with a pH value of 2.4.

Explanation:

pH of the first sample of acetic acid = 2.4

to know the [H+] concentration in the acetic acid solution, the equation used is:

pH = -log [H+]

[H+] = 10^{-pH}

[H+] = 10^{-2.4}

[H+]  = 3.98 X 10^{-3} M

The concentration of H+ ion in first case is 3.98 X 10^{-3} M, the second sample has ten times less hydronium ion so concentration of first case is divided by 10.

3.98 x 10^{-4} M

Now pH of the sample having 10 times fewer ions of acetic acid:

pH = -log [H+]

putting the values in the above equation:

pH = -log [3.98 x 10^{-4} M]

pH = 3.41

If solution has ten times less hydronium ion the pH will change to 3.41.

8 0
3 years ago
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