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sleet_krkn [62]
3 years ago
5

After Rutherford bombarded gold foil with alpha particles, he concluded that the volume of an atom is mostly empty space. Which

observation led Rutherford to this conclusion?
1. Some of the alpha particles were deflected 180 degrees
2. The paths of deflected alpha particles were hyperbolic.
3. Many alpha particles were absorbed by gold nuclei.
4. Most of the alpha particles were not deflected.
Chemistry
2 answers:
marta [7]3 years ago
5 0

Answer: 4. Most of the alpha particles were not deflected.

Explanation:

Rutherford gave an experiment known as gold foil experiment.

In his experiment, he took a gold foil and bombarded it with alpha particles (carrying positive charge). He thought that the particles will pass straight through the foil, but to his surprise, many of them passed through, some of them deflected their path and a few of them bounced back.

Due to the presence of positive charge on the alpha particles they must be deflected, but as there exists a large empty space as most of the alpha particles pass through without deflection.  

irina [24]3 years ago
4 0
4)
Because if it doesn't deflect in the middle it means that there has to be some space for the alpha particles to go through it. 
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A 50.00-mL solution of 0.0350 M aniline ( Kb = 3.8 × 10–10) is titrated with a 0.0113 M solution of hydrochloric acid as the tit
nexus9112 [7]

Answer:

pH = 3.70

Explanation:

Moles of aniline in solution are:

0.0500L × (0.0350mol / 1L) = <em>1.750x10⁻³ mol aniline</em>

Aniline is in equilibrium with water, thus:

C₆H₅NH₂ + H₂O ⇄ C₆H₅NH₃⁺ + OH⁻ Kb = 3.8x10⁻¹⁰

HCl reacts with aniline thus:

HCl + C₆H₅NH₂ → C₆H₅NH₃⁺ + Cl⁻

At equivalence point, all aniline reacts producing  C₆H₅NH₃⁺.  C₆H₅NH₃⁺ has its own equilibrium with water thus:

C₆H₅NH₃⁺(aq) + H₂O(l) ⇄ C₆H₅NH₂(aq) + H₃O⁺(aq)

Where Ka is defined as:

Ka = [C₆H₅NH₂] [H₃O⁺] / [C₆H₅NH₃⁺] = Kw / Kb = 1.0x10⁻¹⁴ / 3.8x10⁻¹⁰ = <em>2.63x10⁻⁵ </em><em>(1)</em>

<em />

As all aniline reacts producing C₆H₅NH₃⁺, moles in equilibrium are:

[C₆H₅NH₃⁺] = 1.750x10⁻³ mol - X

[C₆H₅NH₂] = X

[H₃O⁺] = X

Replacing in (1):

2.63x10⁻⁵ =  [X] [X] / [1.750x10⁻³ mol - X]

4.6x10⁻⁸ - 2.63x10⁻⁵X = X²

0 = X² + 2.63x10⁻⁵X - 4.6x10⁻⁸

Solving for X:

X = -2.3x10⁻⁴ → False answer, there is no negative concentrations

X = 2.0x10⁻⁴ → Right answer

As [H₃O⁺] = X, [H₃O⁺] = 2.0x10⁻⁴.

Now, pH = -log[H₃O⁺]. Thus, pH at equivalence point is:

<em>pH = 3.70</em>

<em></em>

7 0
3 years ago
Which of the following occurs when a reaction in a solution is at equilibrium and more product is added to the solution?No chang
LenaWriter [7]

Answer:

Equilibrium shifts to produce more reactant

Explanation:

  • <em>Le Châtelier's principle</em> <em>states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.</em>

  • When more product is added to the solution:

<em>This will increase the concentration of the products side, so the reaction will be shifted to the lift side (reactants side) to suppress the increase in the concentration of Products.</em>

<em />

<em>So, the right choice is: Equilibrium shifts to produce more reactant</em>

3 0
3 years ago
Which one of the following pairs of acids and conjugate bases is incorrectly labeled or incorrectly matched? Acid Conjugate Base
vekshin1

Answer : The incorrect option is, (d) NH_4^+/NH_2^-

Explanation :

According to the Bronsted Lowry concept, Bronsted Lowry-acid is a substance that donates one or more hydrogen ion in a reaction and Bronsted Lowry-base is a substance that accepts one or more hydrogen ion in a reaction.

Or we can say that, conjugate acid is proton donor and conjugate base is proton acceptor.

(a) The equilibrium reaction will be,

HF+H_2O\rightleftharpoons F^-+H_3O^+

In this reaction, HF is an acid that donate a proton or hydrogen to H_2O base and it forms F^- and H_3O^+ are conjugate base and acid respectively.

In this reaction, HF/F^- are act as a conjugate acid-base.

(b) The equilibrium reaction will be,

HClO+H_2O\rightleftharpoons ClO^-+H_3O^+

In this reaction, HClO is an acid that donate a proton or hydrogen to H_2O base and it forms ClO^- and H_3O^+ are conjugate base and acid respectively.

In this reaction, HClO/ClO^- are act as a conjugate acid-base.

(c) The equilibrium reaction will be,

H_2O+H_2O\rightleftharpoons OH^-+H_3O^+

In this reaction, H_2O is an acid that donate a proton or hydrogen to

In this reaction, H_2O/OH^- are act as a conjugate acid-base.

(d) The equilibrium reaction will be,

NH_4^++H_2O\rightleftharpoons NH_3+H_3O^+

In this reaction, NH_4^+ is an acid that donate a proton or hydrogen to H_2O base and it forms NH_3 and H_3O^+ are conjugate base and acid respectively.

In this reaction, NH_4^+/NH_3 are act as a conjugate acid-base.

(e) The equilibrium reaction will be,

H_3O^++H_2O\rightleftharpoons H_2O+H_3O^+

In this reaction, H_3O^+ is an acid that donate a proton or hydrogen to H_2O base and it forms

In this reaction, H_3O^+/H_2O are act as a conjugate acid-base.

From this we conclude that that, NH_4^+/NH_2^- pairs of acids and conjugate bases is incorrectly labeled or incorrectly matched.

Hence, the incorrect option is, (d) NH_4^+/NH_2^-

4 0
3 years ago
Which is equal to a cubic centimeter <br><br> 1. cg <br> 2. mL<br> 3. Kg<br> 4. mm
liq [111]

Answer:

1 ml

Explanation:

formula multiply the volume value by one

6 0
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Draw the structures of the two monomers that react together to form this polyurethane polymer
matrenka [14]

The monomers that react together to form polyurethane polymer are diisocyanate and diol.

<h3>What are polymers?</h3>
  • Polymers are a class of natural or synthetic substances
  • It is made up of small units called monomers arranged in a repeated pattern to form large molecules called macromolecules
  • Cellulose and resins are examples of natural polymers
  • Polyethylene and polychloroprene are examples of synthetic polymers.

Polyurethane polymer is made up of monomers diisocyanate and diol. It is mostly used in home furnishing in flexible form. The structures of monomers are as follows:

Learn more about polymers:

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#SPJ4

7 0
2 years ago
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