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dimaraw [331]
3 years ago
9

The pyruvate dehydrogenase complex is subject to allosteric control, especially inhibition by reaction products. The main regula

tory process controlling pyruvate dehydrogenase's activity in eukaryotes is
a. exchange of ADP and ATP on the pyruvate dehydrogenase complex.
b. phosphorylation by ATP, which turns the complex on, and dephosphorylation, which turns the complex off.
c. AMP binding to and activating the enzyme.
d. phosphorylation by ATP, which turns the complex off, and dephosphorylation, which turns the
Chemistry
1 answer:
lana [24]3 years ago
4 0

Answer:

D. Phosphorylation by ATP, which turns the complex off, and dephosphorylation, which turns the complex on.

Explanation:

The pyruvate dehydrogenase complex (PDH) is responsible for the conversion of pyruvate to acetylCoA, the fuel for the citric acid cycle.

The regulation of the activity of PDH is allosterically by the products of the reaction which it catalyses. These products are ATP, acetylCoA and NADH. When their is sufficient fuel available for the needs of the cells in the form of ATP, the complex is turned off by phosphorylation of one of the two subunits of E1 (pyruvate dehydrogenase). This phosphorylation inactivates E1. When the concentration of ATP declines, a specific phosphatase removes the phosphoryl group from E1, thereby activating the complex again.

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If 135.7 J of heat are added to 54.0 g of water initially at 25.0 °C . What is the final temperature of the water?
german

Answer:

The final temperature of the water is 25.6 °C.

Explanation:

We have,

Heat added to water is 135.7 J

Mass, m = 54 g

Initial temperature was 25 °C

It is required to find the final temperature of the water. The heat added when temperature is increased is given in terms of specific heat capacity as :

Q=mc(T_f-T_i)

T_f is final temperature

c is specific heat capacity, for water, c=4.184\ J/g^{\circ} C

So,

T_f=\dfrac{Q}{mc}+T_i\\\\T_f=\dfrac{135.7}{54\times 4.184}+25\\\\T_f=25.6^{\circ} C

So, the final temperature of the water is 25.6 °C.

3 0
3 years ago
if the reaction occurs in the laboratory and produces 2.8 moles of ammonia, calculate the percent yield for the experiment. Use
Helen [10]

The question is incomplete, here is the complete question:

The Haber process can be used to produce ammonia,  NH_3  and it is based on the following reaction.

N_2+3H_2\rightarrow 2NH_3

If the reaction occurs in the laboratory and 5 moles of each hydrogen and nitrogen gas reacts and produces 2.8 moles of ammonia, calculate the percent yield for the experiment. Use the quantity of the product that is produced by the limiting reagent as the theoretical yield.

<u>Answer:</u> The percent yield of the reaction is 84.08 %.

<u>Explanation:</u>

We are given:

Moles of nitrogen gas = 5 mole

Moles of hydrogen gas = 5 mole

For the given chemical equation:

N_2+3H_2\rightarrow 2NH_3

By Stoichiometry of the reaction:

3 moles of hydrogen gas reacts with 1 mole of nitrogen gas

So, 5 mole of hydrogen gas will react with = \frac{1}{3}\times 5=1.67mol of nitrogen gas

As, given amount of nitrogen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrogen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

3 moles of hydrogen gas produces 2 moles of ammonia

So, 5 moles of hydrogen gas will produce = \frac{2}{3}\times 5=3.33mol of ammonia

To calculate the percentage yield of ammonia, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of ammonia = 2.8 moles

Theoretical yield of ammonia = 3.33 moles

Putting values in above equation, we get:

\%\text{ yield of ammonia}=\frac{2.8mol}{3.33mol}\times 100\\\\\% \text{yield of ammonia}=84.08\%

Hence, the percent yield of the reaction is 84.08 %.

8 0
3 years ago
Student A pushed on the cart with a force of 500 N. Student B pushed on the other side of the cart. The cart did not move. How m
Nadusha1986 [10]
I depends on the height of the other side of the cart. If it was lower, 400 N. If Higher, at least 600 N. 
5 0
4 years ago
Roman mixes 12 liters of 8% acid solution with a 20% acid solution, which results in a 16% acid solution. Find the number of lit
inysia [295]
Let the 8% solution be A, the 20% solution be B and the final solution be C.

C = A + B
C = 12 + B

0.16C = 0.08(12) + 0.2(B)
0.16(12 + B) = 0.96 + 0.2B
0.96 = 0.04B
B = 24 Liters

C = 12 + 24
C = 36 Liters
3 0
4 years ago
5 *
Virty [35]

Answer:

A. the charge on their ions

Explanation:

Elements are grouped into the same group in the periodic table if they have the same valence electrons. However, the number of valence electrons an element has, determines the number of charges it can possess.

According to this question, two elements in the same group of the periodic table will have the same charge on their ions because they both have the same number of valence electrons.

5 0
3 years ago
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