We have to calculate the number of carbon atoms present in 2-carat pure diamond.
The number of carbon atoms present in 2-carat pure diamond is: 0.19 X 10²³ number of carbon atom.
Diamond is one allotrope of carbon. Atomic mass of carbon is 12.
Mass of one mole carbon atom is 12 g. One mole carbon contains Avogadro's number i.e, 6.023 X 10²³ number of atoms.
0.40 g diamond contains 0.40/12 moles= 0.033 moles of carbon atom.
So, number of carbon atoms present in 0.40 g diamond (i.e, 0.033 mole diamond) is 0.033 X 6.023 X 10²³= 1.98 X 10²²=0.19 X 10²³ .
Therefore, 0.19 X 10²³ number of carbon atoms are in a 2-carat pure diamond that has a mass of 0.40 g
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Answer:
Dissociation factor = 1.8
Explanation:
Data provided in the question:
Molecular weight of the Procaine hydrochloride = 273
Number of ions contained, n = 2
Fraction Dissociating, α = 80% = 0.8
Now,
the dissociation factor 'i' is given as:
i = 1 + α × ( n - 1 )
on substituting the respective values, we get
i = 1 + 0.8 × ( 2 - 1 )
or
i = 1 + ( 0.8 × 1 )
or
i = 1.8
Answer:
C) philosophical and intuitive speculation
Explanation:
Hi
Leucippus and Democritus proposed the concept of an atom based on philosophical speculation as a way of explaining reality with the scarcity of data available at that time.
The ideas of Leucippus and Democritus were rejected at that time but later retaken by Dalton when proposing his atomic model.
Success with your homework.
11 a- ions would exist in the solution, they can carry charges.
B-solids that are neutral, they wouldn't conduct much of a current.
