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3 years ago

A bag has four balls labeled A, B, C, and D.

Mathematics

1 answer:

denis-greek [22]3 years ago

7 0

Answer:

Step-by-step explanation:

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If we place $8,592.00 in a savings account paying 7.5 percent interest compounded annually, how much will our account accrue to

Reika [66]

Compound Interest Formula is:A = P * ( 1 + r )^nP = $8,592r = 7.5 % = 0.075n = 9.5 ( years )A = 8,592 * ( 1 + 0.075 )^(9.5)A = 8,592 * (1.075)^(9.5)A = 8,592 * 1.9878A = $17,079.48Answer: In 9.5 years there will be $17,079.48 on account.

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3 years ago

Read 2 more answers

A polynomial function can be written as (x + 2)(x + 3)(x − 5). What are the x-intercepts of the graph of this function? (1 point

Marizza181 [45]

Answer:

(-2, 0), (-3, 0), and (5, 0)

Step-by-step explanation:

The x-intercept is found when <em>y = 0</em>.

So, we have to find x when <em>(x + 2)(x + 3)(x - 5) = 0</em>

We can do that by pulling apart all parts, because if one part = 0, the whole thing will have to be too (multiplication property of identity).

1. When x + 2 = 0, x = -2

2. When x + 3 = 0, x = -3

3. When x - 5 = 0, x = 5

That gives us (-2, 0), (-3, 0), and (5, 0)

6 0

3 years ago

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Can someone please help me solve this? I will give brainist for the person who does it correctly.

Rufina [12.5K]

Answer:

Yes the car was speeding

Step-by-step explanation:

s = √(30fd) where

s is the speed of the car in mph
f is the coefficient of friction for the road
d is the length in feet of the skid marks

Substitute d = 41.5 and f = 0.8 into the equation:

s = √(30 x 0.8 x 41.5)

⇒ s = √(996)

⇒ s = 31.55946768...

Therefore, for these data, the speed of the car was 31.56 mph (to the nearest hundredth)

The speed limit was 30 mph, therefore the car was speeding as 31.56 > 30

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3 years ago

For each one of the following statements, indicate whether it is true or false.

dexar [7]

Solution :

a). $\text{Var} (X|Y) =E ((X-E(X|Y))^2 |Y)$

Now, if X = Y, then :

$P(X|Y)=\left\{\begin{matrix} 1,& \text{if } x=y \\ 0, & \text{otherwise }\end{matrix}\right.$

Then, E[X|Y] = x = y

So, $\text{Var} (X|Y) =E((X-X)^2 |Y)$

$=E(0|Y)$

= 0

Therefore, this statement is TRUE.

b). If X = Y , then Var (X) = Var (Y)

And as Var (X|Y) = 0, so Var (X|Y) ≠ Var (X), except when all the elements of Y are same.

So this statement is FALSE.

c). As defined earlier,

$\text{Var} (X|Y) =E ((X-E(X|Y))^2 |Y=y)$

So, this statement is also TRUE.

d). The statement is TRUE because $\text{Var} (X|Y) =E ((X-E(X|Y))^2 |Y=y)$ .

e). FALSE

Because, $\text{Var} (X|Y) =E ((X-E(X|Y=y))^2 |Y=y)$

7 0

3 years ago

In a softball league, 87 players play on seven different teams. Each team has at least 12 players. Which inequality gives the la

Mashutka [201]

Answer:

D) p ≤ 15

Step-by-step explanation:

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3 years ago