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Ugo [173]
3 years ago
14

Suppose M is the midpoint

Mathematics
1 answer:
AysviL [449]3 years ago
6 0

x   =   9

Since M is the midpoint of XY:

XM   =   MY

XM =  2x  +  11

MY  =  5x  -  16

2x  +  11   =  5x  -  16

5x  -  2x   =  11  +  16

3x    =   27

x    =  27/3

x   =   8

Learn more here: brainly.com/question/18315903

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Write an equation for each sentence.
almond37 [142]

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3 0
2 years ago
"We keep tossing a fair coin n = 10^6 million times, write down the outcomes: it gives a Heads-and-Tails-sequence of length n. W
anyanavicka [17]

Answer:

Check the explanation

Step-by-step explanation:

Let X_{i} be the indicator random variable that takes the value 1 if the ith coin is the first coin in a sequence of 19 consecutive heads.

For any sequence of length 19, the starting coin can be from toss i ,

such that i is between 1 and n - 19+1

Thus the number of such sequences is

Kindly check the attached image below for the step by step explanation to the question above.

4 0
3 years ago
Let f(x) = x^2 - 11x - 60.<br> Solve for f(x) using factoring.
Alona [7]
F(x) = X^2 - 11x - 60
Two terms that multiply to -60 and add to -11 so...
F(x) = (X - 15) (x + 4)
Your x-intercepts would be 15 and -4.
4 0
3 years ago
Find the Length of arc . Round to the nearest hundredth.
pshichka [43]
A) 14.66

Arc length is equal to radius multiplied by the central angle in radians not degrees

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=5%20%5Csqrt%7B20%7D%20" id="TexFormula1" title="5 \sqrt{20} " alt="5 \sqrt{20} " align="absmid
SOVA2 [1]

Answer:

Step-by-step explanation:

=5\sqrt{20}

=5\sqrt{2^{2}*5 }

=5\sqrt{2x^{2} }  \sqrt{5}

=5 * 2\sqrt{5}

=10\sqrt{5}

3 0
3 years ago
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