Answer:
Second option: 81y^4 - 16x^2, the difference of squares
Step-by-step explanation:
(9y^2-4x)(9y^2+4x) is a special product named difference of squares, then we can apply this formula:
(a-b)(a+b)=a^2-b^2, with a=9y^2 and b=4x, then:
(9y^2-4x)(9y^2+4x)=(9y^2)^2 - (4x)^2
(9y^2-4x)(9y^2+4x)=(9)^2 (y^2)^2 - (4)^2 (x)^2
(9y^2-4x)(9y^2+4x)=81y^(2*2) - 16x^2
(9y^2-4x)(9y^2+4x)=81y^4 - 16x^2
Your first step should be to plug in the q and f values they give you. q being 20 and f being 16. From there you want to isolate 1/p by subtracting the 1/20 from both sides. You should be left with 1/p = 1/16 - 1/20. This will come out to be 1/80 or 0.0125. Now that one side is 1/p and the other is 1/80 you can multiply both sides by p in order to get 1=1/80 times p which means that p = 80 . Hope this helps
Answer: 1304.7
Step-by-step explanation: just took test
We know that
<span>foci on x-axis-------> is a ellipse with horizontal major axis
the equation is
(x</span>²/a²)+(y²/b²)=1
major axis is th<span>e </span>x<span>-axis with length </span><span>2<span>a
2a=14--------> a=7
</span></span>minor axis is the y<span>-axis with length </span><span>2<span>b
2b=4-----> b=2
the equation is
</span></span>(x²/a²)+(y²/b²)=1------> (x²/7²)+(y²/2²)=1-----> (x²/49)+(y²/4)=1
the answer is(x²/49)+(y²/4)=1
see the attached figure