Answer:
The area of parallelogram 1 is 4 square units greater than the area of parallelogram 2.
Explanation:
If you are confused on how to find areas of parallelogram that don't have any parallel sides to the x/y axes, then create a rectangle around the parallelogram and subtract the areas of the triangle from the total area of the rectangle. Example is shown in desmos below:
(Luckily, the first parallelogram happens to be a square so the method above is not necessary)
Area of first parallelogram:
= 20
Area of second parallelogram:
(4*8) - (2*2 + 6*2) = 16
Answer: The area of parallelogram 1 is 4 square units greater than the area of parallelogram 2.
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