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777dan777 [17]
3 years ago
7

What is the surface area of this square pyramid? Please help

Mathematics
1 answer:
Lana71 [14]3 years ago
7 0
70inches squared
A=a(squared)+2a (square root)a(squared)/4+h(squared)
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Which of the following is a factor of 6x^2+2x-21
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What are the answer of your list ?
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4 years ago
What is the solution to the inequality below?<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%7D%20%20%5Cleqslant%205" id="T
ohaa [14]

Answer:

x \leqslant \sqrt{5} ​

Step-by-step explanation:

Hope this helped!

3 0
3 years ago
A circle has a radius of length r. If you mark off an arc on the circle of length 2r what is the measurement of the angle that s
Inessa05 [86]
A full circle has a circumference of 2πr and an angle of 2π radians.

Set up a proportion:
2πr - 2π rad
2r - x rad

2\pi r \times x = 2\pi \times 2 r \\&#10;2\pi r x=4 \pi r \\&#10;x=\frac{4 \pi r}{2 \pi r} \\&#10;x=2

The answer is D. 2 radians.
6 0
3 years ago
Read 2 more answers
Which description of the graph of y=110x is most accurate?
hodyreva [135]

Answer:

The correct option is;

The graph is a line that rises steeply from left to right and passes through the origin

Step-by-step explanation:

The given equation is y = 110·x

Comparing the given equation to the general equation of a straight line, y = m·x + c

Where;

m = The slope of the straight line graph

c = The y-intercept

We have;

The slope of the given equation, y = 110·x = 110

The y-intercept, which is given by the constant c in the given equation = (0, 0)

Therefore, by the slope of the equation, for each unit increase in x, y increases by 110, therefore, the graph is a straight line that rises steeply and passes through the origin

6 0
3 years ago
What is the prime factorization of 440?
lawyer [7]

Answer:

I would say the correct answer is 2^3 • 5 • 11

Step-by-step explanation:

To find the prime factors, you start by dividing the number by the first prime number, which is 2. If there is not a remainder, meaning you can divide evenly, then 2 is a factor of the number. Continue dividing by 2 until you cannot divide evenly anymore. Write down how many 2's you were able to divide by evenly. Now try dividing by the next prime factor, which is 3. The goal is to get to a quotient of 1.Here are the first several prime factors: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29...

<u>Let's start by dividing 440 by 2 </u>

440 ÷ 2 = 220 -  No remainder! 2 is one of the factors!

220 ÷ 2 = 110 -  No remainder! 2 is one of the factors!

110 ÷ 2 = 55 - No remainder! 2 is one of the factors!

55 ÷ 2 = 27.5 - There is a remainder. We can't divide by 2 even anymore. Let's try the next prime number

55 ÷ 3 = 18.3333 - This has a remainder. 3 is not a factor.

55 ÷ 5 = 11 - No remainder! 5 is one of the factors!

11 ÷ 5 = 2.2 -There is a remainder. We can't divide by 5 evenly anymore. Let's try the next prime number

11 ÷ 7 = 1.5714 - This has a remainder. 7 is not a factor.

11 ÷ 11 = 1 - No remainder! 11 is one of the factors!

If we put all of it together we have the factors 2 x 2 x 2 x 5 x 11 = 440. It can also be written in exponential form as 2^3 x 5^1 x 11^1.

here is also the factor tree method : -

7 0
3 years ago
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