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charle [14.2K]
3 years ago
11

Can someone help me with my math homework I don't get it and can you please explain how you did it. Also only help me with the h

ighlighter problems...

Mathematics
1 answer:
Vikentia [17]3 years ago
4 0
1) What you see as 3\frac{3}{8} can be also changed to only a fraction, by changing \frac{3}{1} to \frac{24}{8}, but since the question wants 2 as a whole number, we must take out \frac{24}{8} = 2 \frac{8}{8} and then add the 8 eights to the other 3, to get <span>2 \frac{11}{8} 

</span>for # 10- 13, you need to have the same number on the bottom of all the numbers being subtracted, that means turning the number that aren't fractions (like 4) into fraction, and then into fractions with the same denominators.

10) \frac{4}{1} changes to \frac{32}{8} to get \frac{32}{8} -  \frac{3}{8} =  \frac{29}{8} or 3\frac{5}{8}

11)\frac{5}{1} changes to \frac{50}{10} , and 2\frac{3}{10} to \frac{13}{10}to get \frac{50}{10}-\frac{13}{10}=\frac{37}{10} or <span>3\frac{7}{10}</span>

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Answer:

(a)

\bar x = 0.0075

s = 0.0049

(b)

B. The sample is too small to make judgments about skewness or symmetry.

Step-by-step explanation:

Given:

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\begin{array}{ccccccccc}{} & {S} & {u} & {b} &{j} & {e} & {c} & {t} & {s} &{Operator} & {1} & {2} & {3} & {4} & {5} & {6} & {7} & {8} & {1} & 1.326 & 1.337 & 1.079 & 1.229 & 0.936 & 1.009 & 1.179 & 1.289 & 2 & 1.323 & 1.322 & 1.073 & 1.233 & 0.934 & 1.019 & 1.184 & 1.304 \ \end{array}

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\begin{array}{ccccccccc}{} & {S} & {u} & {b} &{j} & {e} & {c} & {t} & {s} &{Operator} & {1} & {2} & {3} & {4} & {5} & {6} & {7} & {8} & {1} & 1.326 & 1.337 & 1.079 & 1.229 & 0.936 & 1.009 & 1.179 & 1.289 & 2 & 1.323 & 1.322 & 1.073 & 1.233 & 0.934 & 1.019 & 1.184 & 1.304 &{|1 - 2|} &0.003 & 0.015 & 0.006 & 0.004 & 0.002 & 0.010 & 0.005 & 0.015 \ \end{array}

The last row which represents the difference between 1 and 2 is calculated using absolute values. So, no negative entry is recorded.

The mean is then calculated as:

\bar x = \frac{\sum x}{n}

\bar x = \frac{0.003 + 0.015 + 0.006 + 0.004 + 0.002 + 0.010 + 0.005 + 0.015}{8}

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Next, calculate the standard deviation (s).

This is calculated using:

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s = \sqrt{0.00002375

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Of the given options (A - E), option B is correct because the sample is actually too small

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