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777dan777 [17]
3 years ago
9

Without looking, Luke picks necklace beads from a bag of 52 beads. Half the beads are rough. The other half are smooth. There ar

e 13 red beads, 13 blue beads, 13 green beads, and 13 black beads.
What is the theoretical probability of selecting a rough bead?
Mathematics
2 answers:
hichkok12 [17]3 years ago
6 0
Answer:
1/2

Explanation
Marizza181 [45]3 years ago
6 0

Answer:

1/2

Step-by-step explanation:

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SORRY! BUT ALL HELP IS REALLY APPRECIATED! AND WOULD LIKE IF YOU COULD HELP A GURL OUT THANKS
Korolek [52]

Answer:

b is the answer trust me i know

Step-by-step explanation:

6 0
3 years ago
Eight less than four times a number is less then 56. What are the possible values of that number?
Mashutka [201]

Answer: B. X<12

Step-by-step explanation:

First we need to find out what number multipled by 4 is less than 56

4 x 12 = 48

56-48 = 8

And 4 is lower/less than 12 so that's why it's B

5 0
3 years ago
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E = mc2<br> please help ive been looking and i can’t find an answer for math.
goldfiish [28.3K]

Answer:

Don't really understand the question, but

7 0
4 years ago
Field book of an land is given in the figure. It is divided into 4 plots . Plot I is a right triangle , plot II is an equilatera
Kazeer [188]

Answer:

Total area = 237.09 cm²

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)

From the figure attached,

Area of the right triangle I = \frac{1}{2}(\text{Base})\times (\text{Height})

Area of ΔADC = \frac{1}{2}(\text{CD})(\text{AD})

                        = \frac{1}{2}(\sqrt{(AC)^2-(AD)^2})(\text{AD})

                        = \frac{1}{2}(\sqrt{(13)^2-(19-7)^2} )(19-7)

                        = \frac{1}{2}(\sqrt{169-144})(12)

                        = \frac{1}{2}(5)(12)

                        = 30 cm²

Area of equilateral triangle II = \frac{\sqrt{3} }{4}(\text{Side})^2

Area of equilateral triangle II = \frac{\sqrt{3}}{4}(13)^2

                                                = \frac{(1.73)(169)}{4}

                                                = 73.0925

                                                ≈ 73.09 cm²

Area of rectangle III = Length × width

                                 = CF × CD

                                 = 7 × 5

                                 = 35 cm²

Area of trapezium EFGH = \frac{1}{2}(\text{EF}+\text{GH})(\text{FJ})

Since, GH = GJ + JK + KH

17 = \sqrt{9^{2}-x^{2}}+5+\sqrt{(15)^2-x^{2}}

12 = \sqrt{81-x^2}+\sqrt{225-x^2}

144 = (81 - x²) + (225 - x²) + 2\sqrt{(81-x^2)(225-x^2)}

144 - 306 = -2x² + 2\sqrt{(81-x^2)(225-x^2)}

-81 = -x² + \sqrt{(81-x^2)(225-x^2)}

(x² - 81)² = (81 - x²)(225 - x²)

x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴

144x² - 11664 = 0

x² = 81

x = 9 cm

Now area of plot IV = \frac{1}{2}(5+17)(9)

                                = 99 cm²

Total Area of the land = 30 + 73.09 + 35 + 99

                                    = 237.09 cm²

7 0
3 years ago
Calvin had 30 minutes in time-out. For the first 23 1/3 minutes, Calvin counted spots on the ceiling. For the rest of the time,
scoundrel [369]

Answer: \frac{20}{3}\ minutes or 6 \frac{2}{3}\ minutes

Step-by-step explanation:

For this exercise you can convert the mixed number to an improper fraction:

1. Multiply the whole number part by the denominator of the fraction.

2. Add the product obtained and the numerator of the fraction (This will be the new numerator).

3. The denominator does not change.

Then:

23\frac{1}{3}= \frac{(23*3)+1}{3}= \frac{70}{3}\ minutes

You know that he had 30 minutes in time-out, he counted spots on the ceiling for \frac{70}{3} minutes and the rest of the time he made faces at his stuffed tiger.

Then, in order to calculate the time Calvin spent making faces at his stuffed tiger, you need to subract 30 minutes and \frac{70}{3} minutes:

30\ min-\frac{70}{3}=(\frac{3(30)-70}{3})=\frac{20}{3}\ minutes or 6 \frac{2}{3}\ minutes

7 0
3 years ago
Read 2 more answers
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