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777dan777 [17]
3 years ago
9

Without looking, Luke picks necklace beads from a bag of 52 beads. Half the beads are rough. The other half are smooth. There ar

e 13 red beads, 13 blue beads, 13 green beads, and 13 black beads.
What is the theoretical probability of selecting a rough bead?
Mathematics
2 answers:
hichkok12 [17]3 years ago
6 0
Answer:
1/2

Explanation
Marizza181 [45]3 years ago
6 0

Answer:

1/2

Step-by-step explanation:

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A rectangular painting is 2 feet<br>long and 5/6 foot wide. What is<br>the area of the painting?​
AlladinOne [14]

Answer:

1 2/3 sq ft

The drawing will help

4 0
3 years ago
Pls help me with the question
lesya692 [45]

Answer:

The cost of lemons

Step-by-step explanation:

This is because the cost of lemons depends on the amount of lemons purchased.

8 0
3 years ago
Please help me out with this geometry
Natalka [10]

Answer:

(x-[-7])^{2} +(y-[9])=[25]

Step-by-step explanation:

Center (h,k) = (-7, 9)

Radius, r = 5

<u>Equation</u>: (x-h)^{2} +(y-k)^{2} =r^{2}

(x-(-7))^{2} +(y-9)^{2} =(5)^{2}

5^{2} =25

So, (x-(-7))^{2} +(y-9)=25

<u>OAmalOHopeO</u>

6 0
3 years ago
How to find AMN and ANM
zysi [14]
The triangle ANM is similar to triangle ACB. That means they share the same angles. Both AMN and ANM are 75.



3 0
4 years ago
Find the surface area of a regualar pyramid that is a pentagonal pyramid with the area of a base is is 440.4mm and a height of 2
Inessa [10]

Answer:

1240.4 mm²

Step-by-step explanation:

The surface area of a pyramid = Area of the all sides + Area of base

Each side is a triangle.

With a regular pentagonal pyramid, the area of each triangle is

A = \frac{1}{2}\times\text{base}\times\text{slant height}

For the 5 triangles,

A = 5\times\frac{1}{2}\times\text{base}\times\text{slant height} = \frac{1}{2}\times5\times\text{base}\times\text{slant height}

Substituting given values,

A = 5\times\frac{1}{2}\times16\ \text{mm}\times20\ \text{mm} = 800 \text{mm}^2

Area of base = 440.4 mm²

Surface area of a pyramid = 800 + 440.4 mm² = 1240.4 mm²

6 0
3 years ago
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