Answer:
The following two equations model this relationship.
Step-by-step explanation:
We know that when 'y' varies inversely with 'x', we get the equation
y ∝ 1/x
y = k / x
k = yx
where 'k' is called the 'constant of proportionality'.
In our case, it is given that the cube root of 'r' varies inversely with the square of 's', then
∝ 
![\:\sqrt[3]{r}=\:\frac{k}{s^2}](https://tex.z-dn.net/?f=%5C%3A%5Csqrt%5B3%5D%7Br%7D%3D%5C%3A%5Cfrac%7Bk%7D%7Bs%5E2%7D)
or
∵ ![\sqrt[3]{r}=r^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Br%7D%3Dr%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
Therefore, the following two equations model this relationship.