Answer: I think A
Step-by-step explanation:
Answer:
i) where the digits can repeat
1. 30
2. 50
3. 33
4. 55
5. 35
6. 53
ii) where the digits cannot be repeated
3. 35
4. 53
s10 = -20
n = 10
an = -20
solution
s10 = n\2 [a+(n-1)d]
-20 = 10a2[a+(10-1)4]
-4 = a +36
a1 = -40
Hope it helps.
Hope it helps