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3 years ago

1/5+1/7+3/21 the answer is

Mathematics

1 answer:

inessss [21]3 years ago

4 0

Answer:

Step-by-step explanation:

We need to get all the fractions with a common denominator before we can solve the problem.

The only fractions that have a common multiple are 1/7 and 3/21, so we'll add these first and then add 1/5.

1/7 = 3/21

Add

$\frac{3}{21} + \frac{3}{21} =\frac{6}{21}$

6/21 = 30/105

1/5 = 21/105

$\frac{30}{105} + \frac{21}{105} = \frac{51}{105}$

Simplify

$\frac{51}{105} / \frac{3}{3} =\frac{17}{35}$

<h3>ANSWER: 17/35</h3>

I'm always happy to help :)

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What are the focus and directrix of the parabola with the equation y=1/12 x^2

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<h2>Answer:</h2>

$\boxed{y=-3}$

<h2>Step-by-step explanation:</h2>

The graph of this parabola is shown below. From this graph we know that:

VERTEX:

$(h,k)=(0,0)$

DIRECTIX:

Since the vertex lies on the origin and the parabola opens upward, then the standard form of this parabola is:

$x^2=4py$

So:

$y=\frac{1}{12}x^2 \\ \\ \therefore 12y=x^2 \ or \ x^2=12y \\ \\ \\ Then: \\ \\ 4p=12 \therefore p=3$

Then the directrix is:

$y=k-p \\ \\ \therefore y=0-3 \therefore \boxed{y=-3}$

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3 years ago

Find the values of x and y.

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Answer:Input : A = 12, B = 8

Output : X = 2, Y = 10

Input : A = 12, B = 9

Output : -1

Step-by-step explanation:

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2 years ago

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Mamont248 [21]

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3 years ago

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3. Tickets to a show cost $5.50 for adults and 54.25 for students. A family is purchasing2

bulgar [2K]

Step-by-step explanation:The cost of an adult ticket to the show is $5.5

The cost of a student ticket to the show is $4.25

A family is purchasing 2 adult tickets and 3 student tickets. This means that the total cost of 2 adult tickets would be

2 × 5.5 = $11

It also means that the total cost of 3 student tickets would be

3 × 4.25 = $12.75

The total cost of 2 adult tickets and 3 student tickets would be

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If the family pays $25, the exact amount of change they should receive is

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2 years ago

One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on

irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna = 237.08 ft

Step-by-step explanation:

The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°

distance from her position to the top of the building = 2475 ft

distance from her position to the top of the flag = 2615 ft

(a) How far away from the base of the building is the surveyor located?

using the SOHCAHTOA principle

cos 34° = c/2475

c = 0.8290375726 × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b = 0.5591929035 × 2475

b = 1384.0024361

b = 1384.00 ft

(c) What is the angle of elevation from the surveyor to the top of the antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ = 0.784665392

∅ = cos-1 0.784665392

∅ = 38.310258303

∅ = 38.31°

(d) How tall is the antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) = 0.6199159917 × 2615

(a + b) = 1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00 = 237.08031822 ft

Height of antenna = 237.08 ft

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3 years ago