Answer:
7.64% probability that they spend less than $160 on back-to-college electronics
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Probability that they spend less than $160 on back-to-college electronics
This is the pvalue of Z when X = 160. So
has a pvalue of 0.0763
7.64% probability that they spend less than $160 on back-to-college electronics
Answer:
12
Step-by-step explanation:
since i helped can i have brainlist please :D
Answer:
y=-1/8
Step-by-step explanation:
Add 1/4 to -3/8
Answer:
-5 2/3 points per minute
Step-by-step explanation:
change / time = (-85 points)/(15 minutes) = -17/3 points/minute = -5 2/3 points/minute
Answer:
it 5.5⋅10−^8m
Step-by-step explanation:
Unless I'm missing something important here, you can find the difference between the two wavelengths by subtracting one from the other. Since you're interested in finding how much longer the wavelength associated with the orange light is, subtract the wavelength of the green light from the wavelength of the orange light. You know that the two measured wavelengths are 6.15 ⋅ 10 − 7 m → orange light 5.6 ⋅ 10 − 7 m → green light Therefore, the difference between the two wavelengths will be Δ wavelength = 6.15 ⋅ 10 − 7 m − 5.6 ⋅ 10 − 7 m = 5.5 ⋅ 10 − 8 m
