Between 2 and 3, should be somewhere before .5
the answer is y=4x-11
use y+1=4x-12
move 1 to negative because move to the other side
so the answer is y=4x-11
Answer:
Using either method, we obtain: 
Step-by-step explanation:
a) By evaluating the integral:
![\frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%20%5Cint%5Climits%5Et_0%20%7B%5Csqrt%5B8%5D%7Bu%5E3%7D%20%7D%20%5C%2C%20du)
The integral itself can be evaluated by writing the root and exponent of the variable u as: ![\sqrt[8]{u^3} =u^{\frac{3}{8}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7Bu%5E3%7D%20%3Du%5E%7B%5Cfrac%7B3%7D%7B8%7D)
Then, an antiderivative of this is: 
which evaluated between the limits of integration gives:
and now the derivative of this expression with respect to "t" is:
b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:
"If f is continuous on [a,b] then
is continuous on [a,b], differentiable on (a,b) and 
Since this this function 
is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:
Answer:
theres no picture so I cant help you
Step-by-step explanation:
Alright! When you have a constant to a power times another constant to a power (ex. [x^3 times x^3] ) you simply add the powers and keep the base [x^6]. When you have a power to a power (ex. [(12^3)^3] ) you multiply the powers and keep the base [12^9]. When you have a constant to a power divided by a constant to a power (ex. [ x^2 divided by x^5] ) you subtract the powers and keep the base. It's hard to see the questions, so I'll leave this here for you to use as a guide.
