There are 18 coins total in her bag:
7+3+8=18coins
3 of the 18 coins are dimes, so the odds of first drawing a dime are 3/18
P(dime)=3/18
Since the nickel was taken out and not replaced, there are now 17 coins in her purse.
18-1=17coins
8 of the 17 remaining coins are nickels, so the odds of drawing a nickel are 8/17.
P(nickel)=8/17
Now we multiply the two probabilities by eachother to find out the odds of both occurring...
P(dime)*P(nickel)=
3/18*8/17=24/306=8/103=0.078=8%
The probability of grabbing a dime and then a nickel are 8/103 or 0.078 or an 8% chance, whichever way you'd prefer to write it.
Ill break it down for you so you can understand.
We use a method called "long division" to help us divide large numbers. But, if it does not go in, we need to make it into a decimal. Observe.
4 ⟌19
Four does not go into one. (Start with the first number then go right if it doesn't go in.) ((Also add a 0 up top)
0
4 ⟌19
4 does not go into 19 but it can go into 16. (Put a four at the top.)
04
4 ⟌19
-16
____
3
Now, if it can't go in, then put a point after the 4 and add a zero to the three.
04.75
4 ⟌19
-16
____ (4 x 7)
30 28
-28
____
2 (0) (5 x 4)
20 20
_____
0
Your answer is 04.75 OR 4.75.
Hope this helps. Also have a lovely day! ~Pooch ♥
Answer:
x=20
Step-by-step explanation:
I hope this helps. Sorry if i'm wrong.
Answer:
S8 = 112
Step-by-step explanation:.
The question is incomplete
Assuming we are given the following
First term a =7
number of terms n = 8.
Common difference d=2
We can find the sum of the first 8terms S8
Substitute the given values
S8 = 8/2[2(7)+(8-1)(2)]
S8 =4(14+7(2))
S8=4(14+14)
S8 = 4(28)
S8 = 112
Hence the sum of the first 8terms is 112
Note that the values are assumed values
