2 years ago

Evaluate this function at x = 2: f(x)= 3x + 20 *

Mathematics

2 answers:

trasher [3.6K]2 years ago

5 0

Answer:

Step-by-step explanation:

Fitst, you substitute

f(2) = 3(2) + 20

f(2) = 6 + 20

f(2) = 26

your answer is 26

r-ruslan [8.4K]2 years ago

4 0

Answer:

c.) 26

Step-by-step explanation:

f(2) = 3(2) + 20

f(2) = 6 + 20

f(2) = 26

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3 years ago

How to show these 2 problems are inverses

nataly862011 [7]

$\bf \begin{cases}
f(x)=\sqrt[3]{7x-2}\\\\
g(x)=\cfrac{x^3+2}{7}
\end{cases}\\\\
-----------------------------\\\\
now
\\\\
f[\ g(x)\ ]\implies f\left[ \frac{x^3+2}{7} \right]\implies \sqrt[3]{7\left[ \frac{x^3+2}{7} \right]-2}\implies \sqrt[3]{x^3+2-2}
\\\\\\
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-----------------------------\\\\
or
\\\\
g[\ f(x)\ ]\implies g\left[\sqrt[3]{7x-2}\right]\implies \cfrac{\left[\sqrt[3]{7x-2}\right]^3+2}{7}
\\\\\\
\cfrac{7x-2+2}{7}\implies \cfrac{7x}{7}\implies x$

thus f[ g(x) ] = x indeed, or g[ f(x) ] =x, thus they're indeed inverse of each other

8 0

2 years ago