I'm assuming a quarter-circle is exactly 1/4 of a circle. Thus if you have 4 congruent quarter-circles, that should mean they make a complete circle.
If that is the case, then we can find the area of the full circle using pi*r^2.
So the area of the circle is 5^2*pi or 25pi.
To find the area of the shaded region, we subtract the area of the circle from the area of the square.
The area of the square is 10^2 or 100.
So the area of the shaded region is 100 - 25pi.
My calculator says that equals roughly 21.46
P=18
l=5 cm greater than the width
w=5 less than the length
USE YOUR NUMBER SENSE!!! - just plug in different number below 4 to figure out the width
3=w 3+5=8 8+8=16+6=22 WILL NOT WORK
2=w 2+5=7 7+7=14 14+2+2= 18 WE HAVE A WINNER!!!!
FInal Answer: width: 2 cm and length: 7 cm
Yes because it is a linear equation
So,first step is to write ![(fog)(-4)) =f[g(-4)] \\](https://tex.z-dn.net/?f=%20%28fog%29%28-4%29%29%20%3Df%5Bg%28-4%29%5D%20%5C%5C%20)
Now we start from inner paranthesis
,we need to first find value of
![g(-4) =\frac{\sqrt{12-(-4)}}{3}\\ =\frac{\sqrt{12+4}}{3}\\ =\frac{\sqrt{16}}{3}\\ =\frac{4}{3}\\ (fog)(-4)) =f[g(-4)] =f(\frac{4}{3}) =9(4/3)^{2} =9*(16/9) =144/9 =16](https://tex.z-dn.net/?f=%20g%28-4%29%20%3D%5Cfrac%7B%5Csqrt%7B12-%28-4%29%7D%7D%7B3%7D%5C%5C%20%3D%5Cfrac%7B%5Csqrt%7B12%2B4%7D%7D%7B3%7D%5C%5C%0A%3D%5Cfrac%7B%5Csqrt%7B16%7D%7D%7B3%7D%5C%5C%0A%3D%5Cfrac%7B4%7D%7B3%7D%5C%5C%0A%28fog%29%28-4%29%29%20%3Df%5Bg%28-4%29%5D%20%3Df%28%5Cfrac%7B4%7D%7B3%7D%29%20%3D9%284%2F3%29%5E%7B2%7D%20%3D9%2A%2816%2F9%29%20%3D144%2F9%20%3D16%20)
