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pentagon [3]
3 years ago
5

Please help I need help! This is the only way I will pass this unit

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
4 0
There is no solution.
klio [65]3 years ago
3 0

Answer:

there is no solution love.

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Please help I’ll mark brainliest if u give a small explanation
makvit [3.9K]

Answer:

35

Step-by-step explanation:

yeah becuse 35fttttt

6 0
3 years ago
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ivanzaharov [21]
Consider
.. X = {1, 2, 3, 4}, x = 4
.. Y = {2, 3, 4, 5, 6}, y = 5, w = 3
The elements in X or Y (X ∪ Y) are {1, 2, 3, 4, 5, 6}, n = 6.
.. n = 6 = 4 + 5 - 3

Note that if we just add x and y, we count the common elements twice. In order to just count the common elements once, we need to subtract that count from the total of x and y.

selection B is appropriate.
4 0
3 years ago
Solve.
lions [1.4K]

Answer:

b=9,a=12

Step-by-step explanation:

I solved by substitution:

b = 3/4a  ---> plug this into the other equation

a + b = 21   is now    a + 3/4a = 21

Reduce: 7/4a = 21

a = 12

Now solve for b:

b=3/4a is now b=3/4(12)

b=9

6 0
3 years ago
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Solve the inequality 5u≤8u−21 and write the solution in interval notation
PIT_PIT [208]

Answer:

Step-by-step explanation:

5u\leq 8u-21

Subtract 8u from both sides

-3u\leq -21

Divide by -3 on both sides

u\geq 7

Interval notation: [greater/less than or equal to], (greater or equal to)

[7,∞)

3 0
3 years ago
I need help help please
Nitella [24]

Answer:

I think it is b

Step-by-step explanation:

I hope this is correct

6 0
3 years ago
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